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If B represents the allele for black eyes (dominant) and b represents the allele for orange eyes (recessive), what would be the phenotypic ratio of a cross between a heterozygous black-eyed MendAlien and an orange-eyed MendAlien?
3 black : 1 orange
1 black : 0 orange
1 black : 1 orange
0 black : 1 orange
1 black : 3 orange

1 black: 1 orange

The heterozygous black-eyed MendAlien has the genotype Bb. The orange-eyed MendAlien has the genotype bb. The result of this cross is two Bb offspring and two bb offspring. This means that two of the offspring have black eyes and two of the offspring have orange eyes. This 2:2 ratio then reduces to 1:1

Black eyes are dominant to orange eyes, and green skin is dominant to white skin. Sam, a MendAlien with black eyes and green skin, has a parent with orange eyes and white skin. Carole is a MendAlien with orange eyes and white skin. If Sam and Carole were to mate, the predicted phenotypic ratio of their offspring would be _____.
3 black eyes, green skin : 3 black eyes, white skin : 9 orange eyes, green skin : 1 orange eyes, white skin
1 black eyes, green skin : 1 black eyes, white skin : 1 orange eyes, green skin : 1 orange eyes, white skin
1 black eyes, green skin : 3 black eyes, white skin : 3 orange eyes, green skin : 9 orange eyes, white skin
9 black eyes, green skin : 3 black eyes, white skin : 3 orange eyes, green skin : 1 orange eyes, white skin
There is insufficient information to determine Sam's genotype.

1 black eyes, green skin : 1 black eyes, white skin : 1 orange eyes, green skin : 1 orange eyes, white skin

Sam's genotype is BbGg, and Carole's genotype is bbgg.

In order to determine the genotype of a MendAlien with black eyes and green skin, you would cross this individual with a(n) _____ individual.
BBgg
BBGG
bbgg
BbGg
bbGG

bbgg

A cross between two individuals with black eyes and green skin which results in an individual with orange eyes and white skin is an example of a _____ cross
difficult
dihybrid
monohybrid
trihybrid
test

dihybrid

A phenotypic ratio of 9:3:3:1 in the offspring of a cross indicates that _____.
one parent is homozygous dominant and one parent is homozygous recessive
one parent is homozygous dominant and one parent is heterozygous
both parents are homozygous dominant
one parent is heterozygous and one parent is homozygous recessive
both parents are heterozygous for both genes

Both parents are heterozygous for both genes.
Such a result indicates that the genes assort independently and that, for each gene, the alleles exhibit a dominant/recessive relationship.

A BbGg x bbgg cross yields a phenotypic ratio of approximately 5 black eyes, green skin : 5 orange eyes, white skin : 1 black eyes, white skin : 1 orange eyes, green skin. Which of the following best explains these results?
Mendel's laws of segregation and independent assortment are being violated.
The heterozygous individual is male, and the homozygous individual is female.
Mendel's law of independent assortment is being violated.
The genes for eye color and skin color are co-dominant.
Mendel's law of segregation is being violated

Mendel's law of independent assortment is being violated.

Color blindness is an X-linked recessive trait. A color-blind man has a daughter with normal color vision. What is the genotype of the daughter?
XCXc
XCXC
XcXc
XCY
XcY

XCXc
The XC assures the daughter of normal color vision while she inherits a Xc from her father.

Color blindness is an X-linked recessive trait. A color-blind man has a daughter with normal color vision. She mates with a male who has normal color vision. What is the expected phenotypic ratio of their offspring?
1 normal vision female : 1 color-blind female : 1 normal vision male : 1 color-blind male
All the offspring have normal color vision.
2 normal vision females : 1 normal vision male : 1 color-blind male
3 normal vision female : 1 color-blind male
1 normal vision female : 1 color-blind male

2 normal vision females : 1 normal vision male : 1 color-blind male
The parents, XCXc x XCY, have four possible offspring: XCXC (homozygous normal vision female), XCXc (heterozygous normal vision female), XCY (normal vision male), XcY (color-blind male).

Color blindness is an X-linked recessive trait. A color-blind man has a daughter with normal color vision. She mates with a color-blind male. What is the expected phenotypic ratio of their offspring?
All the offspring have normal color vision.
2 normal vision females : 1 normal vision male : 1 color-blind male
3 normal vision female : 1 color-blind male
1 normal vision female : 1 color-blind female : 1 normal male : 1 color-blind male
1 normal vision female : 1 color-blind male

1 normal vision female : 1 color-blind female : 1 normal male : 1 color-blind male
The parents, XCXc x XcY, have four possible offspring: XCXc (heterozygous normal vision female), XcXc (homozygous color-blind female), XCY (normal vision male), XcY (color-blind male).

Color blindness is an X-linked recessive trait. A woman who is homozygous for normal color vision mates with a color-blind male. What is the expected phenotypic ratio of their offspring?
2 normal vision females : 1 normal vision male : 1 color-blind male
3 normal vision female : 1 color-blind male
All the offspring have normal color vision.
1 normal vision female : 1 color-blind female 1 normal male : 1 color-blind male
1 normal vision female : 1 color-blind male

All the offspring have normal color vision.
The offspring of the parents, XCXC x XcY, are: XCXc (heterozygous normal vision female), XCXc (heterozygous normal vision female), XCY (normal vision male), XCY (normal vision male).

Color blindness is an X-linked recessive trait. A color-blind woman mates with a male with normal color vision. What is the expected phenotypic ratio of their offspring?
1 normal vision female : 1 color-blind female : 1 normal male : 1 color-blind male
1 normal vision daughter : 1 color-blind son
2 normal vision females : 1 normal-vision male : 1 color-blind male
3 normal vision female : 1 color-blind male
All the offspring have normal color vision.

1 normal vision daughter : 1 color-blind son
The offspring of the parents, XcXc x XCY, are: XCXc (heterozygous normal vision female), XCXc (heterozygous normal vision female), XcY (color-blind male), XcY (color-blind male).

Color blindness is an X-linked recessive trait. Under what conditions can an unaffected male have a color-blind daughter?
His mate is color-blind.
He can't.
He is heterozygous for color vision.
His father is color-blind.
His mother is color-blind.

He can't

Hypophosphatemia (vitamin D-resistant rickets) is inherited as an X-linked dominant. An unaffected woman mates with a male with hypophosphatemia. What is the expected phenotypic ratio of their offspring?
1 normal female : 1 female with hypophosphatemia : 1 normal male : 1 male with hypophosphatemia
1 normal daughter : 1 son with hypophosphatemia
1 daughter with hypophosphatemia : 1 normal son
2 normal females : 1 normal male : 1 male with hypophosphatemia
3 normal females : 1 male with hypophosphatemia

1 daughter with hypophosphatemia : 1 normal son
The offspring of the parents, XhXh x XHY , are: XHXh (heterozygous female with hypophosphatemia), XHXh (heterozygous female with hypophosphatemia), XhY (normal male), XhY (normal male).

Hypophosphatemia (vitamin D-resistant rickets) is inherited as an X-linked dominant. A woman without hypophosphatemia and a man with hypophosphatemia have a daughter. The daughter mates with a male without hypophosphatemia. What is the expected phenotypic ratio of their offspring?
2 unaffected females : 1 unaffected male : 1 male with hypophosphatemia
1 unaffected female : 1 female with hypophosphatemia : 1 unaffected male : 1 male with hypophosphatemia
1 unaffected daughter : 1 son with hypophosphatemia
1 daughter with hypophosphatemia : 1 unaffected son
3 unaffected females : 1 male with hypophosphatemia

1 unaffected female : 1 female with hypophosphatemia : 1 unaffected male : 1 male with hypophosphatemia
The offspring of the parents, XHXh x XhY, are: XhXh (homozygous female without hypophosphatemia), XHXh (heterozygous female with hypophosphatemia), XhY (unaffected male), XHY (male with hypophosphatemia).

Suppose that having three nostrils is a Y-linked character. A woman with two nostrils mates with a man with three nostrils. What is the expected phenotypic ratio of their offspring?
1 daughter with two nostrils : 1 son with three nostrils
1 daughter with two nostrils: 1 daughter with three nostrils: 1 son with two nostrils : 1 son with three nostrils
2 daughters with two nostrils: 1 son with two nostrils: 1 son with three nostrils
2 daughters with three nostrils: 1 son with two nostrils: 1 son with three nostrils
2 sons with two nostrils: 1 daughter with two nostrils: 1 daughter with three nostrils

Correct

1 daughter with two nostrils : 1 son with three nostrils
The offspring of the parents, XX x XYE, are: XX (female with two nostrils), XX (female with two nostrils), XYE (male with three nostrils), XYE (male with three nostrils).

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