KB Geometry Vocab
About this set
Created by:
KrystaBruce on September 25, 2012
Subjects:
Log in to favorite or report as inappropriate.
Order by
18 terms
Terms | Definitions |
|---|---|
 Complementary angles | Two angles whose sum is 90 degrees (right angle). Each of the two angles are called complements of the other |
| Supplementary angles | Two angles whose sum is 180 degrees (straight angle). Each of the two angles are called the supplements of the other |
| perpendicular | Lines, rays, or segments that intersect at right angles (90 degrees) |
| Vertical angles | non-adjacent angles forrmed when two lines intersect |
| opposite rays | two collinear rays that have a common endpoint and extend in opposite directions. |
| CPCTC | Corresponding Parts of Congruent Triangles are Congruent |
| radius | a segment tfrom the center of the circle to a point on the edge of the circle |
| Median of a Triangle | a line segmeny drawn from any vertex of the triangle to the midpoint of the opposite side |
| Altitude of a Triangle | a line segment drawn from any vertex of the triangle to the opposite side, extends if necessary, and is perpendicular to that side |
| Acute Triangle | A triangle in which all angles are acute |
| Obtuse Triangle | A triangle in which one of the angles is obtuse |
| Isosceles Triangle | A triangle in which atleast two sides are congruent |
| Equilateral Triangle | A triangle in which all sides are congruent |
| Scalene Triangle | A triangle which no two sides are congruent |
| Distance | The distance between 2 objects is the length of the shortest path joining them |
| Perpendicular Bisector (of segment) | Line that bisects and is perpendicular to the segment |
| Theorem 24 | If 2 points are each equidistant from the endpoints of a segment, then the 2 points determine the perpendicular bisector of that segment |
| Theorem 25 | If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of that segment |
First Time Here?
Welcome to Quizlet, a fun, free place to study. Try these flashcards, find others to study, or make your own.