5 Written Questions
5 Matching Questions
- Given 172.16.0.0/18, What are the valid subnets?
- What is the maximum number of IP addresses that can be assigned to hosts on a local subnet that uses the 255.255.255.224 subnet mask?
- What's the broadcast address of each subnet?
- Why subnet?
- a A /27 (255.255.255.224) is 3 bits on and 5 bits off. This provides 8 subnets, each with 30 hosts. Does it matter if this mask is used with a Class A, B or C network address? Not at all. The amount of hosts bits would never change.
- b 11111000 = 248
- c 0.0, 64.0, 128.0, and 192.0
- d Reduced network traffic
- e The number just before the next subnet; the broadcast of the last subnet is always 255
5 Multiple Choice Questions
- 2y - 2 where y is the number of unmasked bits (or 0's)
- A point-to-point link uses only two hosts. A /30, or 255.255.255.252, mask provides two hosts per subnet.
- 11000000 = 192
- Ping 127.0.0.1 (loopback), Ping the local host, Ping Default Gateway (router), Ping remote destination
5 True/False Questions
192.168.100.37/28 → /29 is 255.255.255.248. The fourth octet is a block size of 8. 0, 8, 16, 24. The host is in the 16 subnet, broadcast of 23. Valid host 17-22
Unable to Ping Local Host → Problem with the NIC; Replace the NIC
Classful Routing → all interfaces within the classful address space have the same subnet mask
192.168.100.66/27 → /25 is 255.255.255.128. The fourth octet is a block size of 128. 0, 128. The host is in the 0 subnet, broadcast of 127. Valid host 1-126
Given 172.16.0.0/18, How many subnets? → 2