5 Written Questions
5 Matching Questions
- What is the subnetwork number of a host with an IP address of 172.16.66.0/21?
- Able to ping but still unable to communicate
- Why subnet?
- What subnet and broadcast address is the IP address 172.16.10.33 255.255.255.224 (/27) a member of?
- Your router has the following IP address on Ethernet0: 172.16.2.1/23. Which of the following can be valid host ID's on the LAN interface attached to the router?
- a the 10.32 subnet; The broadcast is 10.63
- b Simplified management
- c Possible DNS problem
- d A /21 is 255.255.248.0, which means we have a block size of 8 in the third octet, so we just count by 8 until we reach 66. The subnet in this question is 64.0. The next subnet is 72.0, so the broadcast address of the 64 subnet is 71.255.
- e The routers IP address on the E0 interface is 172.16.2.1/23, which is a 255.255.254.0. This makes the third octet a block size of 2. The routers interface is in the 2.0 subnet, the broadcast address is 3.255 because the next subnet is 4.0. The valid host range is 2.1 through 3.254. The router is using the first valid host address in the range.
5 Multiple Choice Questions
- Create many networks using subnet masks of different lengths from one network
- The subnet is 172.16.64.0. The broadcast must be 172.16.127.255
- A /29 (255.255.255.248), regardless of the class of address, has only three hosts bits. Six hosts is the maximum amount of hosts on this LAN, including the router interface.
- 11000000 = 192
- A Class C subnet mask of 255.255.255.224 is 3 bits on and 5 bits off (11100000) and provides 8 subnets, each with 30 hosts. However, if the command ip subnet-zero is not used, then only 6 subnets would be available for use.
5 True/False Questions
What is the subnetwork address for a host with the IP address 184.108.40.206/28? → This is a pretty simple question. A /28 is 255.255.255.240, which means that our block size is 16 in the fourth octet. 0, 16, 32, 48, 64, 80, etc. The host is in the 64 subnet.
Subnet Mask → 32-bit value that allows the recipient of IP packets to distinguish the network ID portion of the IP address from the host ID portion of the IP address
192.168.100.25/30 → /25 is 255.255.255.128. The fourth octet is a block size of 128. 0, 128. The host is in the 0 subnet, broadcast of 127. Valid host 1-126
What is the broadcast address of 192.168.192.10/29? → /23 is 255.255.254.0. The third octet is a block size of 2. 0, 2, 4. The subnet is in the 16.2.0 subnet, the broadcast address is 16.3.255
How many valid hosts per subnet? → The numbers between the subnets and the broadcasts omitting the all 0s and all 1s