5 Written Questions
5 Matching Questions
- Unable to Ping Remote Destination
- IP Subnet-Zero
- Given 172.16.0.0/18, What's the broadcast address for each subnet?
- Given 172.16.0.0/18, What are the valid subnets?
- What subnet and broadcast address is the IP address 172.16.50.10 255.255.224.0 (/19) a member of?
- a The subnet is 172.16.32.0, and the broadcast must be 172.16.63.25
- b 0.0, 64.0, 128.0, and 192.0
- c Remote physical network problem between NIC and destination; Additional troubleshooting required at destination
- d 63.255, 127.255, 191.255, 255.255
- e allows you to use the first and last subnet in your network design; turned this command on by default
5 Multiple Choice Questions
- A /30, regardless of the class of address, has a 252 in the fourth octet. This means we have a block size of 4 and our subnets are 0, 4, 8, 12, 16, etc. Address 14 is obviously in the 12 subnet.
- Possible DNS problem
- all interfaces within the classful address space have the same subnet mask
- 11000000 = 192
5 True/False Questions
Why subnet? → 2^x where x is the number of masked bits (or 1's)
What is the subnet for host ID 10.16.3.65/23? → The numbers between the subnets and the broadcasts omitting the all 0s and all 1s
Additional Cisco Troubleshooting → Ping 127.0.0.1 (loopback), Ping the local host, Ping Default Gateway (router), Ping remote destination
You have an interface on a router with the IP address of 192.168.192.10/29. What is the broadcast address the hosts will use on this LAN? → A /29 (255.255.255.248) has a block size of 8 in the fourth octet. This means the subnets are 0, 8, 16, 24, etc. 10 is in the 8 subnet. The next subnet is 16, so 15 is the broadcast address.
What are the valid subnets? → 256 - subnet mask = block size; start with 0 and add the block size until the mask value is reached