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5 Written Questions

5 Matching Questions

  1. What subnet and broadcast address is the IP address 172.16.10.33 255.255.255.224 (/27) a member of?
  2. Given 172.16.0.0/18, What are the valid hosts?
  3. /28
  4. What subnet and broadcast address is the IP address 172.16.46.255 255.255.240.0 (/20) a member of?
  5. How many valid hosts per subnet?
  1. a 11110000 = 240
  2. b 2y - 2 where y is the number of unmasked bits (or 0's)
  3. c the 10.32 subnet; The broadcast is 10.63
  4. d .0.1 - .63.254, .64.1 - .127.254, .128.1 - .191.254, .192.1 - .255.254
  5. e This subnet address must be in the 172.16.32.0 subnet, and the broadcast must be 172.16.47.255

5 Multiple Choice Questions

  1. /27 is 255.255.255.224. The fourth octet is a block size of 32. Count by 32s until you pass the host address of 66. 0, 32, 64. The host is in the 32 subnet, broadcast address of 63. Valid host range of 33-62.
  2. /29 is 255.255.255.248. This is a block size of 8 in the fourth octet. 0, 8, 16. The host is in the 8 subnet, broadcast is 15
  3. The subnet is 172.16.45.12, with a broadcast of 172.16.45.15
  4. Create many networks using subnet masks of different lengths from one network
  5. Facilitated spanning of large geographical distances

5 True/False Questions

  1. 192.168.100.99/25/25 is 255.255.255.128. The fourth octet is a block size of 128. 0, 128. The host is in the 0 subnet, broadcast of 127. Valid host 1-126

          

  2. A router receives a packet on an interface with a destination address of 172.16.46.191/26. What will the router do with this packet?Discard it; by default will discard any broadcast packets

          

  3. You have an interface on a router with the IP address of 192.168.192.10/29. What is the broadcast address the hosts will use on this LAN?A /29 (255.255.255.248), regardless of the class of address, has only three hosts bits. Six hosts is the maximum amount of hosts on this LAN, including the router interface.

          

  4. What is the subnetwork address for a host with the IP address 200.10.5.68/28?This is a pretty simple question. A /28 is 255.255.255.240, which means that our block size is 16 in the fourth octet. 0, 16, 32, 48, 64, 80, etc. The host is in the 64 subnet.

          

  5. Given 192.168.10.0/28, How many hosts per subnet?16,382

          

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