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5 Written questions

5 Matching questions

  2. Given, What are the valid hosts?
  3. Unable to Ping Remote Destination
  4. What subnet and broadcast address is the IP address (/19) a member of?
  5. Given, How many subnets?
  1. a The subnet is, and the broadcast must be
  2. b .1 - .126 & .129 - .254
  3. c /30 is The valid subnet is, broadcast is, and valid hosts are and 26
  4. d 4
  5. e Remote physical network problem between NIC and destination; Additional troubleshooting required at destination

5 Multiple choice questions

  1. 32-bit value that allows the recipient of IP packets to distinguish the network ID portion of the IP address from the host ID portion of the IP address
  2. A /21 is, which means we have a block size of 8 in the third octet, so we just count by 8 until we reach 66. The subnet in this question is 64.0. The next subnet is 72.0, so the broadcast address of the 64 subnet is 71.255.
  3. 256 - subnet mask = block size; start with 0 and add the block size until the mask value is reached
  4. This subnet address must be in the subnet, and the broadcast must be
  5. 11111100 = 252

5 True/False questions

  1. Additional Windows TroubleshootingTracert, Show ip arp


  2. Given, What's the broadcast address for each subnet?0 & 128


  3. Given, How many hosts per subnet?16,382


  4. Classful Routing ProtocolsRIPv1 and IGRP


  5. Using the illustration from the previous question, what would be the IP address of S0 if you were using the first subnet? The network ID is and you need to use the last available IP address in the range. Again, the zero subnet should not be considered valid for this questionA /28 is a mask. The first subnet is 16 (remember that the question stated not to use subnet zero) and the next subnet is 32, so our broadcast address is 31. This makes our host range 17-30. 30 is the last valid host.


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