5 Written Questions
5 Matching Questions
- Why subnet?
- You have an interface on a router with the IP address of 192.168.192.10/29. Including the router interface, how many hosts can have IP addresses on the LAN attached to router interface?
- IP Subnet-Zero
- What is the subnetwork address for a host with the IP address 184.108.40.206/28?
- How many valid hosts per subnet?
- a allows you to use the first and last subnet in your network design; turned this command on by default
- b 2y - 2 where y is the number of unmasked bits (or 0's)
- c A /29 (255.255.255.248), regardless of the class of address, has only three hosts bits. Six hosts is the maximum amount of hosts on this LAN, including the router interface.
- d Simplified management
- e This is a pretty simple question. A /28 is 255.255.255.240, which means that our block size is 16 in the fourth octet. 0, 16, 32, 48, 64, 80, etc. The host is in the 64 subnet.
5 Multiple Choice Questions
- /30 is 255.255.255.252. The valid subnet is 192.168.100.24, broadcast is 192.168.100.27, and valid hosts are 192.168.100.25 and 26
- .1 - .126 & .129 - .254
- You need 5 subnets, each with at least 16 hosts. The mask 255.255.255.240 provides 16 subnets with 14 hosts—this will not work. The mask 255.255.255.224 provides 8 subnets, each with 30 hosts. This is the best answer.
- Traceroute, Arp -a, Ipconfig /all
5 True/False Questions
What is the maximum number of IP addresses that can be assigned to hosts on a local subnet that uses the 255.255.255.224 subnet mask? → A /27 (255.255.255.224) is 3 bits on and 5 bits off. This provides 8 subnets, each with 30 hosts. Does it matter if this mask is used with a Class A, B or C network address? Not at all. The amount of hosts bits would never change.
Given 192.168.10.0/28, How many subnets? → 2
Variable Length Subnet Masks (VLSMs) → 32-bit value that allows the recipient of IP packets to distinguish the network ID portion of the IP address from the host ID portion of the IP address
If an Ethernet port on a router were assigned an IP address of 172.16.112.1/25, what would be the valid subnet address of this host? → A /25 mask is 255.255.255.128. Used with a Class B network, the third and fourth octets are used for subnetting with a total of 9 subnet bits, 8 bits in the third octet and 1 bit in the fourth octet. Since there is only 1 bit in the fourth octet, the bit is either off or on—which is a value of 0 or 128. The host in the question is in the 0 subnet, which has a broadcast address of 127 since 128 is the next subnet.
A router receives a packet on an interface with a destination address of 172.16.46.191/26. What will the router do with this packet? → A /25 mask is 255.255.255.128. Used with a Class B network, the third and fourth octets are used for subnetting with a total of 9 subnet bits, 8 bits in the third octet and 1 bit in the fourth octet. Since there is only 1 bit in the fourth octet, the bit is either off or on—which is a value of 0 or 128. The host in the question is in the 0 subnet, which has a broadcast address of 127 since 128 is the next subnet.