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5 Written questions

5 Matching questions

  1. Classless Routing Protocols
  2. Subnet Mask
  3. Why subnet?
  4. Given 192.168.10.0/28, What's the broadcast address for each subnet?
  5. What is the subnetwork address for a host with the IP address 200.10.5.68/28?
  1. a This is a pretty simple question. A /28 is 255.255.255.240, which means that our block size is 16 in the fourth octet. 0, 16, 32, 48, 64, 80, etc. The host is in the 64 subnet.
  2. b 32-bit value that allows the recipient of IP packets to distinguish the network ID portion of the IP address from the host ID portion of the IP address
  3. c 127 & 255
  4. d RIPv2, EIGRP, or OSPF
  5. e Simplified management

5 Multiple choice questions

  1. /25 (with ip subnet-zero), /26, /27, /28, /29, /30
  2. Tracert, Show ip arp
  3. IP stack failure; Reinstall TCP/IP
  4. the subnet is 80.0 and the broadcast address is 95.255
  5. Optimized network performance

5 True/False questions

  1. /2911110000 = 240

          

  2. Given 192.168.10.0/28, How many hosts per subnet?16,382

          

  3. Your router has the following IP address on Ethernet0: 172.16.2.1/23. Which of the following can be valid host ID's on the LAN interface attached to the router?A /29 (255.255.255.248) has a block size of 8 in the fourth octet. This means the subnets are 0, 8, 16, 24, etc. 10 is in the 8 subnet. The next subnet is 16, so 15 is the broadcast address.

          

  4. What subnet and broadcast address is the IP address 172.16.66.10 255.255.192.0 (/18) a member of?The subnet is 172.16.32.0, and the broadcast must be 172.16.63.25

          

  5. Additional Windows TroubleshootingTraceroute, Arp -a, Ipconfig /all

          

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