5 Written questions
5 Matching questions
- Classless Routing Protocols
- Subnet Mask
- Why subnet?
- Given 192.168.10.0/28, What's the broadcast address for each subnet?
- What is the subnetwork address for a host with the IP address 126.96.36.199/28?
- a This is a pretty simple question. A /28 is 255.255.255.240, which means that our block size is 16 in the fourth octet. 0, 16, 32, 48, 64, 80, etc. The host is in the 64 subnet.
- b 32-bit value that allows the recipient of IP packets to distinguish the network ID portion of the IP address from the host ID portion of the IP address
- c 127 & 255
- d RIPv2, EIGRP, or OSPF
- e Simplified management
5 Multiple choice questions
- /25 (with ip subnet-zero), /26, /27, /28, /29, /30
- Tracert, Show ip arp
- IP stack failure; Reinstall TCP/IP
- the subnet is 80.0 and the broadcast address is 95.255
- Optimized network performance
5 True/False questions
/29 → 11110000 = 240
Given 192.168.10.0/28, How many hosts per subnet? → 16,382
Your router has the following IP address on Ethernet0: 172.16.2.1/23. Which of the following can be valid host ID's on the LAN interface attached to the router? → A /29 (255.255.255.248) has a block size of 8 in the fourth octet. This means the subnets are 0, 8, 16, 24, etc. 10 is in the 8 subnet. The next subnet is 16, so 15 is the broadcast address.
What subnet and broadcast address is the IP address 172.16.66.10 255.255.192.0 (/18) a member of? → The subnet is 172.16.32.0, and the broadcast must be 172.16.63.25
Additional Windows Troubleshooting → Traceroute, Arp -a, Ipconfig /all