ochem exam 3

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chelsiejoe  on November 16, 2011

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ochem exam 3

dipole dispersion forces, pulls molecules together
Van der waals
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dipole dispersion forces, pulls molecules together Van der waals
What has a higher VDW radius than methyl? iodine
Haloalkane BP polarizability of the unshared electrons of the halogen atom
Density of haloalkanes greater than that of other hydrocarbons of similar MW bc of the halogen's larger mass-to-volume ratio
Alkane to haloalkane? free radical halogenation (Cl2 or Br2 + light) replaces in the order--allylic>3>2>1>methyl
regioselectivity of halogenation greater for bromination than chlorination (due to Hammond's postulate)
BDEs bond dissociation enthalpies--of homolytic bond cleavage for a given type of bond (BDEs bonds broken-BDEs bonds made=overall energetics of rxn)

Exothermic rxns have negative values overall
the three parts of radical chain mechanism chain initiation (radicals formed from nonradical compounds), chain propagation (a radical and a molecule react to given a new radical and new molecule), termination (radicals destroyed; add one of each together)
Hammond's postulatetransition state of an exothermic rxn occurs early and looks more like the reactants; thus changes in reactants have a larger effect on the rate

endothermic occurs later and looks more like the products

*for both chlorination and bromination of alkanes, the RDS is the extraction of a H to form an alkyl radical (endo for bromination/exo for chlorination)
allylic substitution adding a halogen to a carbon next to a double bond
*proceeds by a radical chain mechanism
**bc of delocalization of unp e density through resonance, the allyl radical is more stable than the tert butyl radical
chlorination/bromination of alkanes 1. happens with HEAT OR LIGHT through radical chain mechanism
2. take a hydrogen from the carbon bonded to the most carbon atoms and replace with the halogen
alkene to haloalkene (allylic bromination) 1. high temps (heat initiates radical mech) using the halogens themselves
2. then bromination using NBS is initiated by light
3. also use Ch2Cl2
alkenes to bromoalkane (under radical conditions) 1. adds H AND Br to LESS sub'd carbon of double bond (breaks double bond)
2. radical chain mechanism
3. so you need HBr + peroxides
4. *ADDS BOTH BY NON MARKOV
Sn2 stereochem INVERSION AT CHIRAL CENTER (turns R to S and vice versa)
Sn1 stereochem results in RACEMIZATION (50% R/50% S)
haloalkane structure haloalkanes that can form more stable carbocations react faster in an Sn1 mechanism
1. shifts can occur
What prevents Sn2? steric hindrance on the backside of the C-Lv (bulk around the rxn site)
leaving group ability the more stable the anion produced upon rxn, the greater Lv group ability
protic solvents H bond DONORS (most contain -OH groups)
aprotic solvents cannot donate an H (diethyl ether, DMS, DMF)
polar solvents interact strongly with ions and polar molecules
NP solvents do not act strongly with ions and polar molecules
What measures solvent polarity? dielectric constant
solvolysis Nu sub. rxn where the solvent is the nucleophile
What solvents accelerate sn1? polar protic--by stabilizing the charged carbocation intermediate

*formic acid (HCOOH), ethanol, methanol, acetic acid (CH3COOH), water
What solvents accelerate sn2? polar aprotic--they do not react strongly with the nucleophile

*DCM, THF, DMF, MeCN, DMSO
good Nu generally anions
moderate Nu neutral with one or more available lone pairs
poor Nu polar protic solvents
Nucleophilicity the stronger the interaction of a nucleophile with solvent, the lower the nucleophilicity
What Nu are better for sn2? small Nu with very little steric hindrance
primary haloalk react through sn2... due to an absence of steric hindrance and lack of carbocation stability
secondary haloalk react through sn2... in aprotic solvents with good Nu
secondary haloalk react through sn1... in protic solvents with poor Nu

*E1 is less when sn1 occurs
tertiary haloalk--sn1 bc the steric hindrance makes sn2 impossible, plus the attached alkyl groups stabilize the carbocation
What is b elimination? removal of atoms or groups of atoms from adjacent carbons
haloalkANE to alkENE dehydrohalogenation--b elimination (E1 or E2) that involves loss of an H and a halogen from adjacent carbon atoms (makes a double bond)
Zaitsev's elimination b elimination to give the more stable alkene
E1 Lv departs to give carbocat, then a proton is taken off an adjacent carbon atom (BY A BASE) to create the product alkene

*only depends on [X]
E2 the halogen departs at the same time as the H atom is removed (BY BASE) to create product alkene

*depends on [X] AND [OH]
stereoselectivity of E2 lowest energy transition state is the one in which the Lv group and the H atom that depart are oriented ANTI and COPLANAR (this determines whether E or Z alkenes are produced)

*for cyclohexane derivatives, both Lv and H must be axial
regioselectivity of E1 and E2 both follow Zaisev's as long as Lv and H can be oriented anti coplanar

*the more stable alkene is generally the more sub'd alkene
How to decide between substitution or elimination look at: structure of haloalkane, choice of solvent, and the relative base strength of the nucleophile
What class of haloalkanes do not react through e1/sn1? primary

*SN2 is favored for all Nucleophiles EXCEPT VERY STRONG BASES--where E2 would dominate (H2N- or sterically hindered tert butoxide)
secondary haloalkanes through E2 1. if Nu is strong base (CA w/pKa above 11) such as hydroxide, alkoxide, acetylides, and H2N-
secondary haloalkanes through sn2 weak bases (CAs with pKas lower than 11) that are good or moderate nucleophiles
secondary haloalkanes through e1/sn1 poor nucleophiles (that are polar protic solvents) react through a combo of e1 and sn1 and the exact ratio is hard to predict
tertiary haloalkanes through sn2 NO!!!!
tertiary H.A. through e2 if the Nu is a strong base (CA w/pka above 11)

*(-OH, alkoxide, acetylide, H2N-)
tertiary H.A. through sn1/e1 other Nu in a polar protic solvent gives a combo of sn1/e1
Why are alcohol BP higher than other hydrocarbons of similar MW? because of intermolecular association through hydrogen bonding, increased dispersion forces with increase of MW
Why are alcohols more soluble in water? bc they react with water by H bonding
Alcohols--acids or bases? Both. they can act as weak acids (H donors) or weak bases (H acceptors)
In the presence of strong acid -OH... can be protonated and made into the better Lv group (-OH2)

*this is a common mechanistic scheme in alcohol rxns
alcohols to metal alkoxides Li, Na, K....liberates H2
tertiary alcohols to H.A. HCl, HBr, HI

*carbocat int
primary/secondary alcohols to H.A. PBr3, SOCl2, SOBr2

*sn2 with inversion when replacing alcohol with halogen
*alcohols react with sulfonyl chlorides to give alkyl sulfonates (the sulfonate group is a good leaving group analogoues to a halogen atom)
ALCOHOLS to alKENEs treated with strong acid leads to dehydration, which is elimination of water from adjacent carbon atoms to give an alkene

*Zaitsev's
primary alcohols to CARBOXYLIC ACIDS H2CrO4--first converted to aldehyde, then aldehyde hydrate which is further oxidized to the carboxylic acid
primary alcohols to ALDEHYDES PCC with no water, prevents further oxidation
secondary alcohols to KETONES PCC or H2CrO4
tertiary alcohols are NOT oxidized!

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