# Algebra 1 Midterm Exam Review

### 49 terms by fridldav

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>= means greater than or equal to <= means less than or equal to ^ means the number is squared Some questions require you to graph equations. No graphs will be given. Currently a work in progress. I will update answers as the break continues. Work is shown first. Then the answer is at the bottom.

11 + 8 x 3^ - 8
11 + 8 x 9 - 8
11 + 72 - 8
83 - 8
75

### Evaluate the expression. 2/3 ((5 + 2)^ - 13)

2/3 ((5 + 2)^ - 13)
2/3 (7^ - 13)
2/3 (49 - 13)
2/3 (36)
24

5(3^) - 7(3)
5(9) - 7(3)
45 - 21
24

7(4)-11=17
28-11=17
17=17
yes

9(2) + 3 < 13
18 + 3 < 13
21 < 13
no

### Check whether the given number is a solution of the equation or inequality. 5z - 9 >= 7z - 11; -2

5(2) - 9 >= 7(5) - 11
10 - 9 >= 35 - 11
1 >= 24
no

5 - 13
-8

-17 - 21
-38

15 + 12
27

77

-15/2(-8)
60

-12

13

-3

16 and -16

0.2 and -0.2.

x + 7 = 19
- 7 - 7
x = 12

23 - y = 14
-23 -23
-y = -9
y = 9

7p - 11 = 10
+11 +11
7p = 21
p = 3

q/4 + 8 = 13
-8 -8
q/4(4) = 5(4)
q = 20

22j/22 = 11/22
j = 1/2

### Solve, if possible. 14m + 7 - 8m = -17

14m - 8m + 7 = -17
6m +7 = -17
-7 -7
6m/6 = -24/6
m = -4

### Solve, if possible. -3.1t + 4.3 = -1.9t + 3.7

-3.1t + 4.3 = -1.9t + 3.7
-4.3 -4.3
-3.1t = -1.9t - 0.6
+1.9t +1.9t
-1.2t/-1.2 = -0.6/-1.2
t = 1/2

12k -6 = 16k -32
+6 +6
12k = 16k - 26
-16k -16k
-4k/-4= -26/-4
k = 13/2

### Solve, if possible. 1/3(9g - 6) = 3/5(5g + 15)

3g - 2 = 3g + 9
3g = 3g + 11
no solution/not possible

### A student can read 4 pages in 5 minutes. How many pages can the student read in 60 minutes.

4/5 = 60/x CROSS MULTIPLY
300/4 = 4x/4
x = 75
75 pages

38p/38 = 15.2/38
p = .4
40%

150(.35) = n
n = 52.5
52.5

1250(.74) = b
b = 925
925 students

ax+by=c
ax=-by+c
a=(-by+c)/x

ax-y/b=c
-y/b=-ax+c
-y=-abx+bc
y=abx-bc

### Plot point A(3, 6) on a coordinate plane and describe its location on the graph.

(3, 6) is in Quadrant I.

### Plot point B(-2, -4) on a coordinate plane and describe its location on the graph.

(-2, -4) is in Quadrant III.

### Plot point C(0, -3) on a coordinate plane and describe its location on the graph.

(0, -3) is on the x-axis.

(13-8)/(5-4)
5/1
The slope is 5.

### Find the slope of the line that passes through the points (-3, 6) and (2, 7).

(7-6)/(2--3)
1/5
The slope is 1/5.

### Find the slope of the line that passes through the points (-8, -2) and (-5, -2).

(-2--2)/(-5--8)
0/3
The slope is undefined.

### Graph y-2x=-3.

y-2x=-3
y = 2x + 3
Possible points: (0, 3), (1, 5), (2, 7), (-1, 1), (-2, -1)

### Graph x = -4.

Possible points: (-4, -2), (-4, -1), (-4, 0), (-4, 1), (-4, 2)

### Graph y = 3/5x +3.

Possible points: (-10, -6), (-5, 0), (0, 3), (5, 6), (10, 9)

### Evaluate f(x) = -1/2x + 3 when x = -2.

f(-2) = -1/2(-2) + 3
f(-2) = 1 + 3
f(-2) = 4

### Evaluate g(x) = 8x - 7 when x = 0.5.

g(0.5) = 8(0.5) - 7
g(0.5) = 4-7
g(0.5) = -3

### The amount of water w (in thousands of gallons) flowing over a dams spillway varies directly with time t (in hours). In four hours, six thousand gallons of water flow over the spillway. Write a direct variation equation that related w and t. How many gallons of water will be released in twelve hours?

w = at
6 = 4a
3/2 = a
w = 3/2(12)
w = 18
w = 3/2t; 18 thousand gallons

3 = 2(-1) + b
3 = -2 + b
5 = b
y = 2x + 5

-3 = 3/4(4) +b
-3 = 3 + b
-6 = b
y = 3/4x - 6

-7 = -5(2) +b
-7 = -10 + b
3 = b
y = -5x + 3

### Write an equation in standard form of the line that passes through the point (3, -7) and has a slope of -7.

y + 7 = -7(x - 3)
y + 7 = -7x + 21
y = -7x + 14
7x + y = 14

...

x - 13 < -8
x < 5

Example: