Test: Membrane Potentials - 20 Questions

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5 Written Questions

5 Matching Questions

  1. When should Cl- be used in GHK equation?
  2. What happens with an excess of Sodium influx in respect to driving forces
  3. What equation is Sodium conc used in?
  4. Nernst Equation at Room Temp
  5. Can Cl- contribute to Em?
  1. a Higher Na movement would decrease Driving Force. This is because the membrane has moved slightly towards positive (Na is in higher concentration in the extracellular space). This causes the Driving Force for K to increase because there is now a larger differenc between membrane potential and equilibrium potential for K. This leads to more K moving out of cell and less Na into cell. Eventually the driving forces return to normal.
  2. b Yes, cells that have Na+/K+/Cl- co transporter (ascending loop of henle). If Cl- is pumped into cell and the membrane is permeable there will be outward leak of Cl-. This is a depolarizing effect
  3. c E = [-58/z] log [conc.in/conc.out]
  4. d Goldman-Hodgkin-Katz
  5. e Only when Cl- is not passively distributed.

5 Multiple Choice Questions

  1. This is because the membrane will have a slight pNa which makes the cell more negative than EK+
  2. 3Na+ out for every 2K+ in. This hyperpolarizes cell membrane (more negative)
  3. The presence of inpermeable anions in intracellular space
  4. E = -58log { ([pK*Kin]/[pK*Kout]) + ([pNa*Nain]/[pNa*Naout]) + ([pCl*Clin]/[pCl*Clout]) }
  5. The difference between equilibrium potential and membrane potential

5 True/False Question

  1. Does Cl- contribute to Em in most cells? → Yes, cells that have Na+/K+/Cl- co transporter (ascending loop of henle). If Cl- is pumped into cell and the membrane is permeable there will be outward leak of Cl-. This is a depolarizing effect

          

  2. What type of cells do not obey donnan effect? → Nerve cells do not obey donnan effect

          

  3. Step 2 of DE explanation → Cl- reaches conc equilibrium at 30mM each side. However, large K+ conc grad still exists so K+ still moves out. This means Cl- has to go with it.

          

  4. Rate of Flow → V=IR

          

  5. When DF is equal to 0 → E = ([RT] / [zF]) In (X1/X2)

          

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