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21 terms

CarolynRodgersTEACHER

Power

Force (F) x Distance (d) = Work W

Work

Power= Work ÷ Time

Acceleration

a= (velocity2-velocity1)÷ time

Velocity 2

velocity2= velocity1+ (acceleration×time)

Distance

Distance= Work÷ Force

Time (acceleration)

Time= (velocity2- velocity1)÷ acceleration

Force

Force= Work÷ distance

Work (if you have power and time)

Work=Power × time

Time (power)

time = work ÷ power

A roller coaster car rapidly picks up speed as it rolls down a slope. As it starts down the slope, its speed is 4 m/s. But 3 seconds later, at the bottom of the slope, its speed is 22 m/s. What is its average acceleration?

a= (V2-V1)÷ t

a= (22-4)÷3

A= 18÷3

A=6 m/s/s

a= (22-4)÷3

A= 18÷3

A=6 m/s/s

Amy uses 20N of force to push a lawn mower 10 meters. How much work does she do?

Work= Force×distance

Work= 20 N × 10 m

Work = 200 N/m

Work= 20 N × 10 m

Work = 200 N/m

Frank does 2400J of work in climbing a set of stairs. If he does the work in 6 seconds, what is his power output?

Power= Work ÷ time

Power= 2400 J ÷ 6 s

Power= 400 J/s

Power= 2400 J ÷ 6 s

Power= 400 J/s

A 900N mountain climber scales a 260m cliff. How much work is done by the mountain climber?

Work= Force×distance

Work= 900 N × 260m

Work=234,000 N/m

Work= 900 N × 260m

Work=234,000 N/m

A woman runs a kilometer using a force of 210N and a power output of 500W. How long in minutes does it take this woman to complete 1 kilometer?

Work= Force×distance

Work= 210 N × 1000m

Work= 210,000 N/m

time = work ÷ power

time= 210,000 N/m ÷ 500 W

time= 400 s

Work= 210 N × 1000m

Work= 210,000 N/m

time = work ÷ power

time= 210,000 N/m ÷ 500 W

time= 400 s

A Car accelerates from 2 m/s to 130 m/s in 12 seconds. What is the lizard's average acceleration?

a= (V2-V1)÷ t

a= (130m/s-2m/s)÷ 12s

a= 128m/s ÷ 12s

a= 10.67 m/s/s

a= (130m/s-2m/s)÷ 12s

a= 128m/s ÷ 12s

a= 10.67 m/s/s

If a Ferrari, with an initial velocity of 10 m/s, accelerates at a rate of 50 m/s/s for 3 seconds, what will its final velocity be?

velocity2= velocity1+ (acceleration×time)

V2= 10 m/s + (50 m/s/s × 3s)

V2= 10m/s+150 m/s/s

V2= 160 m/s

V2= 10 m/s + (50 m/s/s × 3s)

V2= 10m/s+150 m/s/s

V2= 160 m/s

Josh rolled a bowling ball down a lane in 2.5 s. The ball traveled at a constant acceleration of 1.8 m/s2 down the lane and was traveling at a speed of 7.6 m/s by the time it reached the pins at the end of the lane. How fast was the ball going when it left Tim's hand?

velocity1= velocity2 - acceleration×time

A runner covers the last straight stretch of a race in 4 s. During that time, he speeds up from 5 m/s to 9 m/s. What is the runner's acceleration in this part of the race?

a= (V2-V1)÷ t

a= (9 m/s- 5 m/s)÷ 4 s

a= 4m/s ÷ 4 s

a= 1m/s/s

a= (9 m/s- 5 m/s)÷ 4 s

a= 4m/s ÷ 4 s

a= 1m/s/s

How much Power is required to pull a sled if you use 60J of work in 5 seconds?

Power= work ÷ time

Power= 60 J ÷ 5s

Power= 12 Watts

Power= 60 J ÷ 5s

Power= 12 Watts

Intial velocity

V1= V2-at

A skateboarder executes 20 leaps across the skate park in 3 minutes. The power it takes her to do this is 12 watts with a force of 30 N. What is the total distance she travelled?

3*60= 180

Work=Power × time

Work= 12W ÷ 180s

Work=2160 J

Distance= Work÷ Force

Distance= 2160 J÷ 30 N

Distance= 72 m

Work=Power × time

Work= 12W ÷ 180s

Work=2160 J

Distance= Work÷ Force

Distance= 2160 J÷ 30 N

Distance= 72 m