The network address of 172.16.0.0/19 provides how many subnets and hosts?

A. 7 subnets, 30 hosts each

B. 7 subnets, 2,046 hosts each

C. 7 subnets, 8,190 hosts each

D. 8 subnets, 30 hosts each

E. 8 subnets, 2,046 hosts each

F. 8 subnets, 8,190 hosts each A (A /28 is a 255.255.255.240 mask. Let's count to the ninth subnet (we need to find

the broadcast address of the eighth subnet, so we need to count to the ninth subnet).

Starting at 16 (remember, the question stated that we will not use subnet zero, so we

start at 16, not 0), 16, 32, 48, 64, 80, 96, 112, 128, 144 etc.. The eighth subnet is 128

and the next subnet is 144, so our broadcast address of the 128 subnet is 143. This

makes the host range 129-142. 142 is the last valid host.)