This set is written for the 'learn' format, it can be used in other formats but it is most effective when set on 'learn'. Hope this can help you out on chem 101 test #2 (unit 4 and 5).

### Cis-trans Isomers

has identical bonding and substituents, only differs in 3-dimenstional arrangement of the substituents in space

### Carbon

Must follow the octet rule in order to achieve a stable configuration by sharing four electrons

### Alkanes

Saturated hydrocarbons containing only carbon to carbon single bonds (derivatives of methane)

### Esterification; produces ester + H2O

organic acid + alcohol (in the presence of an acid catalyst and heat)

### Aromatics

Cyclic organic compounds characterized by the presence of at least one 6 carbon benzene ring

### Substituted Hydrocarbon

in which one or more hydrogen atoms are replaced by another atom or group of atoms ( aka functional groups)

### Organic Chemistry

branch that deals with carbon compounds, including those with no relationship to life.

### Structural Formula

type of organic chemistry formula that shows the actual bonding of atoms to each other

### Hydrolysis

reverse of esterification, requires heat and acid (H+) to catalyze the reaction (yields an organic acid + alcohol)

###
Step 1: Identify the formula needed

mg = (mEq/L) (mGEW) (L)

Step 2: Find the mGEW

Ca- 1 x 23.0 = 23.0

Cl- 1 x 35.5 = 35.5

O- 3 x 16 = 48.0

(23.0) + (35.5) + (48.0) = (106.5) =GMW

TPIV- find valence for ClO3, which is [ -1 ] then find the absolute value which is ( 1 )

mGEW = 106.5 / 1 = 106.5 mg/mEq

Step 3: convert mL to L

9mL = 0.009 L

Step 4: Plug in for the knowns

mg = ( 21.0 mEq/L) (106.5 mg/mEq) (0.009 L)

mg = 20.1285

Round

20.1 mg

How much (mg) NaClO3 is needed to prepare 9mL of a 21.0 mEq/L NaClO3 solution? Round to the tenths place.

###
Step 1: Identify the formula needed

g= (mol/L) (GMW) (L)

Step 2: Convert mL to L

400mL = 0.4L

Step 3: Find the GMW of Na3SO6

Na- 3 x 23.0 = 69.0

S- 1 x 32.1 = 32.1

O- 6 x 16.0 = 96.0

(69) + (32.1) + (96) = 197.1

GMW= 197.1

Step 4: plug in for the knowns

g= (3.00 mol/Eq) (197.1) (0.4L)

236.5g

Determine how many grams of Na3SO6 is needed to prepare 400 mL of a 3.00 mol/L Na3SO6 solution. Round to the tenths place.

### n-butyl group

This formula represents an ethyl (alkyl) group CH2CH3, what group does this formula represent?

CH2CH2CH2CH3

### Prop (3)

Identify which prefix (root) should be used for a 3 carbon chain using IUPAC nomenclature rules.

### Hept (7)

Identify which prefix (root) should be used for a 7 carbon chain using IUPAC nomenclature rules.

### Aldehyde

What type of group yields a primary alcohol upon reduction and an organic acid upon oxidation?

### Sulfhydryl group

Some protein properties depend on the presence of this functional group and this group contributes to protein structure and activity?

*this one may be a little tricky

### Halogenation

this reaction involves the substitution of Hydrogen with one or more Halogens and yields a halogenated alkane

###
Step 1: identify the formula needed

GEW=GMW/TPIV

Step 2: Find TPIV

common valence of (SO3) is [ - 2 ] multiply this by the subscript (3) and then take the absolute value of the answer

- 2 x 3 = - 6 = 6

TPIV= 6

Step 3: Find the GMW

multiply the number of atoms in each element by there atomic mass

Ca- 3 x 40.1 =120.3

S- 3 x 32.1 = 96.3

O- 9 x 16 = 144.0

(120.3) + (96.3) + (144.0) = 360.6 GMW

Step 4: plug in for the knowns and solve

GEW = 360.6 / 6 = 60.1 g/Eq

60.1 g/Eq

Find the GEW for a Ca3(SO3)3 compound.

###
Step 1: Identify formula needed

#moles = grams/GMW *simplified formula

Step 2: Find GMW of NaSO2

Na- 1 x23.0 = 23.0

S- 1 x 32.1 = 32.1

O- 2 x 16 = 32.0

(23.0) + (32.1) + (32.0) = 87.1g/mol = GMW

Step 3: plug in for the knowns and solve

#moles = 293.0 / 87.1 = 3.3639494483

round = 3.3

3.3 moles

Determine the number of moles contained in a 293.0 grams of NaSO2.

###
Step 1: Identify the formula

g=(Eg/L)(GEW)(L)

Step 2: Find the GEW of NaCl4

First find the GMW

Na- 1 x 23.0 = 23.0

Cl- 4 x 35.5 = 142.0

(23.0) + (142.0) = 165.0

GMW = 165.0 g/Eg

Find the TPIV of NaCl4

(Cl) common valence of [ - 1 ]

(-1)x subscript (4) = -(4) take the absolute value of (-4), which will end up being (4)

TPIV = 4

GEW = 165.0 / 4= 41.25g/Eq

Step 3: covert mL into L

275mL = 0.275 L

Step 4: Plug in for the knowns and solve

(89.5g) = (Eq/L)(41.25g/Eq)(0.275L)

(89.5g) = (Eq/L)(11.34375)

(89.5) / (11.34375) = (Eg/L)(11.34375) / (11.34375)

Eg/L = 7.889807162534435

ROUND

7.9 Eq/L

Determine the Eq/L concentration of an NaCl4 solution that was prepared by adding 89.5 grams NaCl4 to a 275mL flask. Round to the tenths place.

### Organic acid + alcohol

Name the product of this reaction ESTERIFICATION: ester + water------- (requires heat and an acid catalyst)

### Amide

Identify this functional group.

O=C - NH2

(product formed between a carboxylic acid and an amine)

### Molecular Formula

A formula used in organic chemistry that states the actual number of each kind of atom found in a molecule

### Secondary Carbon

Carbons that are covalently bonded to two other carbons are classified as what type of carbon?

### Trans-Isomer

Structures with substituents on opposite sides of the carbon ring are called? (across the chain)

### Ester

What type of functional group is this?

O=C - O

(compounds formed by the reaction between carboxylic acid and an alcohol)

###
Step 1: Identify the formula needed

g=(Eq/L)(GEW)(L)

Step 2: Find the GEW of Na(SO4)2

GMW

Na- 1 x 23.0 = 23.0

S- 2 x 32.1 = 64.2

O- 8 x 16 = 128

(23) + (64.2) + (128) = 215.2 g/mol

GMW = 215.2

TPIV

identify the common valence for (SO4), which is [ - 2 ]

Multiply this valence times the subscript (2)

(-2) x (2) = (- 4) take the absolute value of this number, which is (4)

TPIV=4

GEW=GMW/TPIV

GEW=215.2 / 4 = 53.8 g/Eq

Step 2: plug into the formula for the knowns and solve

(64.0g)=(1.9 Eq/L)(53.8 g/Eq)(L)

(64)=(102.22)(L)

(64) / (102.22) = (L) / (102.22)

L = 0.626100567

Step 3: convert L into mL

0.626100567L = 626.100567mL

Round to the nearest tenth

626.1mL

What volume of solution (mL) an be prepared from 64.0 grams of Na(SO4)2 if the desired concentration is 1.9 Eq/L? Round to the nearest tenth.

###
Step 1: Identify the formula needed

g=(mol/L)(L)(GMW)

Step 2: Calculate GMW for CaCO3

Ca- 1 x 40.1 = 40.1

C- 1 x 12 = 12.0

O- 3 x 16 = 48.0

add (40.1) + (12.0) + (48.0) = 100.1 g/mol

GMW= 100.1

Step 3: Plug in the knowns and solve

(34.0g)=(2.7 mol/L)(L)(100.1g/mol)

(34.0)=(270.27)(L)

(34) / (270.27) = (270.27)(L) / (270.27)

(L)= (34) / (270.27)

L= 0.125800126

Round to the tenths place

0.1 L

What volume (L) of CaCO3 solution can be prepared from 34.0 grams of CaCO3 if a 2.7 mol/L CaCO4 solution is desired? Round to the nearest tenths place

###
Step 1: identify the formula needed

g = (mol/L)(GMW)(L)

Step 2: Calculate the GMW (including H2O)

Cu- 1 x 63.5 = 63.5

S- 1 x 32.1 = 32.1

O- 4 x 16 = 64.0

H2O- 6 x 18 = 108.0

add (63.5) + (32.1) + (64.0) + (108.0) = 267.6

GMW = 267.6 g/mol

Step 2: covert mL into L

275mL = 0.275 L

Step 3: Plug values into formula and solve

(g)= (3.2 mol/L)(267.6 g/mol)(0.275L)

g= 235.488

round to the tenths place

235.4g

How much CuSO4 * 6HOH is required to prepare 275 mL of a 3.2 mol/L CuSO4 solution? Round to the tenths place

###
Step 1: Identify the formula needed

g=(Eg/L)(GEW)(L)

Step 2: Find the GEW (include H2O)

GMW

Cu- 1 x 63.5 = 63.5

S- 1 x 32.1= 32.1

O- 4 x 16 = 64.0

H2O- 3 x 18 = 54.0

add (63.5) + (32.1) + (64.0) + (54.0) = 213.6

GMW= 213.6 g/mol

TPIV

find the common valence of (SO4) which is [ - 2 ]

taking the absolute value of this number will be (2)

TPIV= 2

GEW= (213.6) / (2) = 106.8 g/Eq

Step 3: Convert mL into L

600mL= 0.6L

Step 4: Place values into the formula and solve

g=(1.2)(106.8)(0.6)

g=76.896

round to the tenths place

76.9g

Determine how much CuSO4*3H2O is required to prepare 600 mL of a 1.2 Eq/L CuSO4 solution. Round to the tenths place.