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Chapter 2 Chemistry SI Prefixes & Conversions
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Gravity
Terms in this set (12)
Tera (T)
1 Tm = 1,000,000,000,000 m
Giga (G)
1 Gm = 1,000,000,000 m
Mega (M)
1 Mm = 1,000,000 m
Kilo (K)
1 Km = 1,000 m
Hecto (H)
1 Hm = 100 m
Deka (da)
1 dam = 10 m
Deci (d)
10 dm = 1 m
Centi (c)
100 cm = 1 m
Milli (m)
1,000 mm = 1 m
Micro (μ)
1,000,000 μm = 1 m
Nano (n)
1,000,000,000 nm = 1 m
Pico (p)
1,000,000,000,000 pm = 1 m
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Verified questions
PHYSICAL SCIENCE
Explain how some woolly mammoths could have been preserved intact in frozen ground. What conditions must have persisted since the deaths of these animals?
CHEMISTRY
Combustion products from a burner enter a gas turbine at 10 bar and $950^\circ C$ and discharge at 1.5 bar. The turbine operates adiabatically with an efficiency of 77%. Assuming the combustion products to be an ideal-gas mixture with a heat capacity of $32 \mathrm{J} \cdot \mathrm{mol}^{-1} \cdot \mathrm{K}^{-1},$ what is the work output of the turbine per mole of gas, and what is the temperature of the gases discharging from the turbine?
CHEMISTRY
How can i convert centimeters to meters?
CHEMISTRY
The protein lysozyme unfolds at a transition temperature of 75.5 $^ { \circ } C$ and the standard enthalpy of transition is $509 \mathrm { kJmol } ^ { - 1 }$. Calculate the entropy of unfolding of lysozyme at 25.0 $^ { \circ } C$, given that the difference in the constantpressure heat capacities upon unfolding is 6.28 kJ $\mathrm { K } ^ { - 1 } \mathrm { mol } ^ { - 1 }$ and can be assumed to be independent of temperature. Hint: Imagine that the transition at 25.0 $^ { \circ } C$ occurs in three steps: (i) heating of the folded protein from 25.0 $^ { \circ } C$ to the transition temperature, (ii) unfolding at the transition temperature, and (iii) cooling of the unfolded protein to 25.0 $^ { \circ } C$. Because the entropy is a state function, the entropy change at 25.0 $^ { \circ } C$ is equal to the sum of the entropy changes of the steps.