5 Written questions
5 Matching questions
- Unable to Ping Default Gateway
- If an Ethernet port on a router were assigned an IP address of 172.16.112.1/25, what would be the valid subnet address of this host?
- Subnet Mask
- Why subnet?
- a /28 is 255.255.255.240. The fourth octet is a block size of 16. Just count by 16s until you pass 37. 0, 16, 32, 48. The host is in the 32 subnet, with a broadcast address of 47. Valid hosts 33-46
- b A /25 mask is 255.255.255.128. Used with a Class B network, the third and fourth octets are used for subnetting with a total of 9 subnet bits, 8 bits in the third octet and 1 bit in the fourth octet. Since there is only 1 bit in the fourth octet, the bit is either off or on—which is a value of 0 or 128. The host in the question is in the 0 subnet, which has a broadcast address of 127 since 128 is the next subnet.
- c Optimized network performance
- d Local physical network problem between NIC and router
- e 32-bit value that allows the recipient of IP packets to distinguish the network ID portion of the IP address from the host ID portion of the IP address
5 Multiple choice questions
- The subnet is 172.16.45.12, with a broadcast of 172.16.45.15
- allows you to use the first and last subnet in your network design; turned this command on by default
- To test the local stack on your host, ping the loopback interface of 127.0.0.1
- the subnet is 80.0 and the broadcast address is 95.255
- /29 is 255.255.255.248. This is a block size of 8 in the fourth octet. 0, 8, 16. The host is in the 8 subnet, broadcast is 15
5 True/False questions
Variable Length Subnet Masks (VLSMs) → Create many networks using subnet masks of different lengths from one network
Given 172.16.0.0/18, How many subnets? → 2
Variable Length Subnet Masks (VLSMs) → /25 (with ip subnet-zero), /26, /27, /28, /29, /30
How many valid hosts per subnet? → 2y - 2 where y is the number of unmasked bits (or 0's)
What is the subnetwork address for a host with the IP address 188.8.131.52/28? → This is a pretty simple question. A /28 is 255.255.255.240, which means that our block size is 16 in the fourth octet. 0, 16, 32, 48, 64, 80, etc. The host is in the 64 subnet.