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sin^-1 x dx (1 to 0)
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Gravity
Terms in this set (8)
step one: find du and u
u = sin^-1, du = 1/ sr1-x^2
step two: find v and dv
dv = dx , v= x
step 3: set up the formal for uv - vdu
sin^-1
x - x
1?sr1-x^2
step 4: plug in 1 and 0 for x and split up the second half and Usub
1
sin^-1(1) - 0
sin^-1(0) - 1/srU * du/-2
step 5: cross multiply the second half
PI/2 + 1/2 { u^-1/2
step 6: divide U^-1/2 by the power
PI/2 +1/2 [2u^1/2]
step 7: plug in 1 and 0 for U
PI/2 + 0^1/2 - 1^1/2
step 8: final answer!
PI/2 - 1
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