## Which is the equation of a parabola with focus (-5, 3) and vertex (-5, 6)? a. -12(7-6) = (x+5) C (x+5)2 =-12(y-6) b. (+ 5)

Question

Which is the equation of a parabola with focus (-5, 3) and vertex (-5, 6)?

a. -12(7-6) = (x+5)

C (x+5)2 =-12(y-6)

b. (+ 5)² = -30(7-6)

d. (x+5)2 = -12(7-6)

Please select the best answer from the choices provided

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2021-10-12T21:45:36+00:00
2021-10-12T21:45:36+00:00 2 Answers
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## Answers ( )

Answer:Which is the equation of a parabola with focus (-5, 3) and vertex (-5, 6)?

Focus and Vertex are both on x = –5, so that’s the Axis of Symmetry.

Distance from Vertex to Focus is p = 3-6 = –3.

4p(y-k) = (x-h)^2

4(–3)(y–6) = (x-(-5))^2

–12(y–6) = (x+5)^2

y = (–1/12)(x+5)^2 + 6 <== Answer

Distance from Vertex to Directrix is –p = 3.

Directrix is y = 6+3 = 9.

Step-by-step explanation:Answer: On edg its C: (x+5)^2 = -12(y-6)

Step-by-step explanation: