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Newts will develop more neurotoxin overtime because the ones without enough neurotoxin will eventually get eaten and die and the ones with resistance will survive and pass down their high levels of toxicity to their offspring. This is also an advantageous trait which increase rate of survival for newts and will therefore give a higher production rate.
If garter snakes from the newt-free east coast were introduced to the poison newt's territory there is no indication whether their offspring would adapt and develop a resistance to the newt's poison. This is due to mutations occurring randomly and there is no telling when or if these mutations will occur. However, if there was a mutation to gain this resistance then eventually this mutation will become prominent within the population for it will be advantageous to them.

-0.5 Stay steady or increase. With selection the average should definitely increase.
2.5 points Newt toxicity should increase as the least toxic newts will be eaten whereas the most toxic would escape predation.

-0.5 said 'we cannot predict what will happen' or something like that. That is not true -- if there is no resistance they will die or eat other things, if there is some resistance that will be selected for, a random mutation suddenly in the exact right place is highly unlikely
-1.5 Predicting that resistance would definitely happen over time.
-1.5 does not explain why on second part of the question.
2.5 points: the new snakes would not quickly develop a resistance, they would probably die or eat non-newts. The resistance would have to come from a random mutation, which is pretty unlikely to suddenly happen in the exact right place in the genome.
The chart below shows heterozygosity (grey bar) and the inbreeding coefficient for cats (black bar). Inbreeding coefficient approaches 1 when there is a great deal of inbreeding and 0 when there is none. Small populations will have high inbreeding coefficients (because here are fewer individuals so animals that are more closely related will be more likely to breed with each other) To the left of the grey line on the bottom are breeds of cats (Singapura through Siberian). To the right of the grey division along the x-axis (between Siberian and Kenya) are random bred cats (mutts) from the localities listed. The last three on the right are wild cat populations. Felis silvestris silvestris is a small wild cat native to Europe and much of Africa, Felis silvestris caffra is the South African wildcat and Felis silvestris tristami (another wild cat). Given these data, which of the following statements are true? (lipinski et al 2007 Genomics). Please note, these data are based on microsattelites in the genome not on coding regions, they can be used to make predictions, but shouldn't be taken as the final word.

Select one or more:
a. Random bred cats would probably be able to adapt to changes in the environment better than cat breeds
b. The low heterozygosity in Felis silvestris silvestris (F.S. silvestris) could be due to a large population.
c. The cat with the smallest gene pool is the Singapura.
d. The low heterozygosity in Felis silvestris silvestris (F.S. silvestris) could be due to a very small population.
e. f. silvestris has a larger gene pool than Maine Coon cats.