Mass to Mass + Combustion

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How to solve a M2M problem
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Terms in this set (13)
-The amount of product that could form when the limiting reagent runs out
-The maximum amount that could form
Example: 3 scoops of ice cream + 1 cone =1 ice cream cone.
-The limiting Reagent is the cones, so the theoretical yield is 1 ice cream cone because that is how much formed when the limiting reagent (waffle cones) are completely used up.
-the number of the limiting reagent is the theoretical yield.
-a measure of how well the reaction went.
-a comparison to what you actually got in the experiment to what you should have gotten (theo. yield.)
Equation:
Actual Yield/Theoretical Yield. x100

Example: 8/10=80% yield which means you attempted to make 10 ice cream cones but only had 8 waffle cones, so that is how many you could make in total.
Can you determine how much of the excess reactant is left over in both grams and mL?-Need to do a third M2 M problem to find how much of the excess was used. -Use Theo. yield and convert to excess reagent. This is how you find out how much excess reagant was used. -Then subtract the used from what you started with.If given two amounts of reactants in both grams & volumes, can you determine which will be the limiting reagent; the reagent in excess; the theoretical yieldCan you write a balanced equation for a complete combustion reaction? Incomplete combustion? Can you ID the type of combustion based on Limiting reagents?Complete combustion reaction: Fuel + O2--> CO2 + H20 Incomplete: Fuel + O2--> CO2 + CO + C + H2O -The limiting reagent for incomplete combustion is Oxygen. (Excess is fuel) -The limiting reagent for complete combustion is fuel. (Excess is oxygen).