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Science
Chemistry
chem nomenclature lets get it
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Flashcards
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Terms in this set (80)
O 2-
oxide
O2 2-
peroxide
OH -
hydroxide
S 2-
sulfide
SO4 2-
Sulfate
SO3 2-
Sulfite
S2O3 2-
Thiosulfate
HSO4 -
hydrogen sulfate (bisulfate)
HSO3 -
hydrogen sulfite (bisulfite)
F -
fluoride
Cl -
Chloride
ClO4 -
Perchlorate
ClO3 -
Chlorate
ClO2 -
Chlorite
ClO -
hypochlorite
Br -
bromide
BrO4 -
Perbromate
BrO3 -
Bromate
BrO2 -
Bromite
BrO -
Hypobromite
I -
iodide
IO4 -
Periodate
IO3 -
Iodate
IO2 -
Iodite
IO -
hypoiodite
N 3-
nitride
NO3 -
nitrate
NO2 -
Nitrite
P 3-
Phosphide
PO4 3-
Phosphate
CN -
Cyanide
OCN -
Cyanate
SCN -
Thiocyanate
CO3 2-
Carbonate
HCO3 -
Bicarbonate
C2O4 2-
Oxalate
CrO4 2-
chromate
Cr2O7 2-
Dichromate
MnO4 -
Permanganate
OAC -
Acetate (1)
C2H3O2 -
Acetate (2)
CH3COO -
Acetate (3)
CH3CO2 -
Acetate (4)
SiO4 4-
silicate
AsO3 3-
Arsenite
AsO4 3-
Arsenate
BO3 3-
borate
HPO4 2-
hydrogen phosphate
H2PO4 -
dihydrogen phosphate
Al 3+
Aluminum
NH4 +
Ammonium
Cd 2+
Cadmium
H +
Hydrogen
Zn +
Zinc
Ag +
Silver
As 3+
Arsenic (III)
As 5+
Arsenic (V)
Bi 3+
Bismuth (III)
Cr 2+
Chromium (II)
Cr 3+
Chromium (III)
Co 2+
Cobalt (II)
Co 3+
Cobalt (III)
Cu +
Copper (I)
Cu 2+
Copper (II)
Au +
Gold (I)
Au 3+
Gold (III)
Fe 2+
Iron (II)
Fe 3+
Iron (III)
Fe 6+
Iron (VI)
Pb 2+
Lead (II)
Pb 4+
Lead (IV)
Mn 2+
Manganese (II)
Mn 3+
Manganese (III)
Mn 4+
Manganese (IV)
Hg2 2+
Mercury (I)
Hg 2+
Mercury (II)
Ni 2+
Nickel (II)
Ni 3+
Nickel (III)
Sn 2+
Tin (II)
Sn 4+
Tin (IV)
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In the flood stage, a natural channel often consists of a deep main channel plus two floodplains. The floodplains are often shallow and rough. If the channel has the same slope everywhere, how would you analyze this situation for the discharge? Assume that $y_1=20 \mathrm{ft}, y_2=$ $5 \mathrm{ft}, b_1=40 \mathrm{ft}, b_2=100 \mathrm{ft}, n_1=0.020$, and $n_2=0.040$, with a slope of $0.0002$. Calculate the discharge in $\mathrm{ft}^3 / \mathrm{s}$.
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The defender in a catalytic oxidizer manufacturing plant has a market value of $130,000 and expected annual operating costs of$70,000 with no salvage value after its remaining life of 3 years. The depreciation charges for the next 3 years will be $69,960,$49,960, and $35,720. Using an effective tax rate of 35%, determine the CFAT for next year only that should be used in a present worth equation to compare this defender against a challenger that also has a 3-year life. Assume the company’s after-tax MARR is 12%.
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