8.6 Solve Radical Equations

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how do you get the square root out of the square root?
you square it
4x2/3=36
4x2/3=36 (divide by 4 on both sides) x2/3=9= x=27
why should you check your solutions?
to check if its an extraneous solution
what is an extraneous solution?
an apparent solution that must be rejected because it does not satisfy the original equation
2+ square root r = 11
minus 2 on both sides= (square root r) ∧2= (9)∧2 r=81
----check-------------------------
2+ square root 81 =11
2+9 =11 √