5 terms

how do you get the square root out of the square root?

you square it

4x2/3=36

4x2/3=36 (divide by 4 on both sides) x2/3=9= x=27

why should you check your solutions?

to check if its an extraneous solution

what is an extraneous solution?

an apparent solution that must be rejected because it does not satisfy the original equation

2+ square root r = 11

minus 2 on both sides= (square root r) ∧2= (9)∧2 r=81

----check-------------------------

2+ square root 81 =11

2+9 =11 √

----check-------------------------

2+ square root 81 =11

2+9 =11 √