## Related questions with answers

Question

$180 ^ { \circ } < \alpha < 360 ^ { \circ }$

and

$\cos \alpha = \frac { 8 } { 17 }$

. Find the following.

$\sin \frac { \alpha } { 2 }$

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 3Given in problem : $\cos\alpha=\dfrac{8}{17}$

We have to find the value of $\sin\dfrac{\alpha}{2}$ so we will use the **Half-angle formula**.

$\sin\dfrac{\alpha}{2}=\pm\sqrt{\dfrac{1-\cos\alpha}{2}}$

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