## Related questions with answers

What is the difference between the probability density and the radial probability density?

Solution

Verified$\textbf{a.)}$ We have to find angular momentum of hydrogen atom in a $6s$ state.

We know that, the $6s$ state is described by $n=6$ and $l=0$ .

So, from equation for the orbital angular momentum, we have :

$\begin{align*} L&=\sqrt{l(l+1)}\hbar\\ L&=\sqrt{0(0+1)}\hbar \tag{Substitute values in equation.}\\ L&=0\\ \end{align*}$

$\textbf{b.)}$ We have to find angular momentum of hydrogen atom in a $4f$ state.

We know that, the $6s$ state is described by $n=4$ and $l=3$ .

So, from equation for the orbital angular momentum, we have :

$\begin{align*} L&=\sqrt{l(l+1)}\hbar\\ L&=\sqrt{3(3+1)}\hbar \tag{Substitute values in equation.}\\ L&=\sqrt{3(4)} \hbar\\ L&=\sqrt{12}\hbar\\ \end{align*}$

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