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  1. Write the equation y+2=14(x+3)y + 2 = \frac { 1 } { 4 } ( x + 3 ) in the following forms: a. Slope-intercept form b. Standard form c. Standard form with a positive x-term d. Standard form with no fractions or decimals

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a. Slope-intercept form is y=mx+by=mx+b so solve the equation for yy to write it in slope-intercept form:

y+2=14(x+3)y+2=14x+34Distribute.y=14x+342Subtract 2 on both sides.y=14x+3484Get a common denominator.y=14x54Subtract the fractions.\begin{align*} y+2&=\frac{1}{4}(x+3)\\ y+2&=\frac{1}{4}x+\frac{3}{4}&&\text{Distribute.}\\ y&=\frac{1}{4}x+\frac{3}{4}-2&&\text{Subtract 2 on both sides.}\\ y&=\frac{1}{4}x+\frac{3}{4}-\frac{8}{4}&&\text{Get a common denominator.}\\ y&=\frac{1}{4}x-\frac{5}{4}&&\text{Subtract the fractions.} \end{align*}

b. Standard form is Ax+By=CAx+By=C so move the xx-term of the slope-intercept form to the left side:

y=14x54Slope-intercept form.14x+y=54Subtract 14x on both sides.\begin{align*} y&=\frac{1}{4}x-\frac{5}{4}&&\text{Slope-intercept form.}\\ -\frac{1}{4}x+y&=-\frac{5}{4}&&\text{Subtract $\frac{1}{4}x$ on both sides.} \end{align*}

c. Multiply both sides of the standard form from part b by 1-1 to write the standard form with a positive xx-term:

14x+y=54Standard form from part b.1(14x+y)=1(54)Multiply both sides by 1.14xy=54Distribute and multiply.\begin{align*} -\frac{1}{4}x+y&=-\frac{5}{4}&&\text{Standard form from part b.}\\ -1\left(-\frac{1}{4}x+y\right)&=-1\left(-\frac{5}{4}\right)&&\text{Multiply both sides by $-1$.}\\ \frac{1}{4}x-y&=\frac{5}{4}&&\text{Distribute and multiply.} \end{align*}

d. Multiply both sides of the standard form from part c by 4 to eliminate the fractions:

14xy=54Standard form from part c.4(14xy)=4(54)Multiply both sides by 4.x4y=5Distribute and multiply.\begin{align*} \frac{1}{4}x-y&=\frac{5}{4}&&\text{Standard form from part c.}\\ 4\left(\frac{1}{4}x-y\right)&=4\left(\frac{5}{4}\right)&&\text{Multiply both sides by 4.}\\ x-4y&=5&&\text{Distribute and multiply.} \end{align*}

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