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Question

3x+2y=43x+2y=4

2x3y=62x-3y=-6

Solution

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Step 1
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We are given:

3x+2y=4(1)3x+2y=4\tag{1}

2x3y=6(2)2x-3y=-6\tag{2}

Solve by elimination. Here, I decided tp eliminate yy first. Multipy (1) by 3 to obtain (3):

9x+6y=12(3)9x+6y=12\tag{3}

Multipy (2) by 2 to obtain (4):

4x6y=12(4)4x-6y=-12\tag{4}

Add each side of (3) and (4) and solve for xx

13x=013x=0

x=0x=0

Solve for yy using (2):

3(0)+2y=43(0)+2y=4

2y=42y=4

y=2y=2

So, the solution of the system is:

(0,2)\color{#c34632}(0,2)

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