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Question

25s49t225s^4-9t^2

Solution

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We are given:

25s49t225s^4-9t^2

This is a difference of two squares so we use the rule: a2b2=(ab)(a+b)a^2-b^2= (a-b)(a+b). From the given, a2=25s4a^2=25s^4 so a=5s2a=5s^2 and b2=9t2b^2=9t^2 so b=3tb=3t. Hence, we factor as:

(5s23t)(5s2+3t)\color{#c34632}(5s^2-3t)( 5s^2+3t)

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