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A 1200-kg car traveling initially at vCi=25.0m/sv_{\mathrm{C} i}=25.0 \mathrm{m} / \mathrm{s} in an easterly direction crashes into the back of a 9000-kg truck moving in the same direction at vTi=20.0m/sv_{\mathrm{T} i}=20.0 \mathrm{m} / \mathrm{s}. The velocity of the car immediately after the collision is vCf=18.0m/sv_{C f}=18.0 \mathrm{m} / \mathrm{s} to the east. (a) What is the velocity of the truck immediately after the collision? (b) What is the change in mechanical energy of the car-truck system in the collision? (c) Account for this change in mechanical energy.

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Given\textbf{\underline{Given}}:

mC=1200  kgm_C=\textcolor{#c34632}{1200\;\mathrm{kg}}

vCi=25  m/sv_{Ci}=\textcolor{#c34632}{25\;\mathrm{m/s}}

mT=9000  kgm_T=\textcolor{#c34632}{9000\;\mathrm{kg}}

vTi=20  m/sv_{Ti}=\textcolor{#c34632}{20\;\mathrm{m/s}}

vCf=18  m/sv_{Cf}=\textcolor{#c34632}{18\;\mathrm{m/s}}

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