## Related questions with answers

A 1200-kg car traveling initially at $v_{\mathrm{C} i}=25.0 \mathrm{m} / \mathrm{s}$ in an easterly direction crashes into the back of a 9000-kg truck moving in the same direction at $v_{\mathrm{T} i}=20.0 \mathrm{m} / \mathrm{s}$. The velocity of the car immediately after the collision is $v_{C f}=18.0 \mathrm{m} / \mathrm{s}$ to the east. (a) What is the velocity of the truck immediately after the collision? (b) What is the change in mechanical energy of the car-truck system in the collision? (c) Account for this change in mechanical energy.

Solution

Verified$\textbf{\underline{Given}}$:

$m_C=\textcolor{#c34632}{1200\;\mathrm{kg}}$

$v_{Ci}=\textcolor{#c34632}{25\;\mathrm{m/s}}$

$m_T=\textcolor{#c34632}{9000\;\mathrm{kg}}$

$v_{Ti}=\textcolor{#c34632}{20\;\mathrm{m/s}}$

$v_{Cf}=\textcolor{#c34632}{18\;\mathrm{m/s}}$

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