Question

A 15-g bullet is fired from a rifle. It takes

2.50×103s2.50 \times 10 ^ { - 3 } \mathrm { s }

for the bullet to travel the length of the barrel, and it exits the barrel with a speed of 715 m/s. Assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet.

Solution

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Concept: \textbf{Concept: }

As we know the core of classical mechanics is Newton's three laws of motion which the basic classical laws describing motion. As we know the Newton's first law assigns that if the net force on an object s zero, an object originally at rest remains at rest, and an object in motion remains in motion in a straight line with constant velocity.

Also, we know that Newton's second law assigns that the acceleration of an object is directly proportional to the net force acting on it, and inversely proportional to its mass

F=m a\begin{align*} \sum F &= m ~ a \end{align*}

As we know Newton's third law assigns that whenever one object exerts a force on a second object, the second object always exerts a force on the first object which is equal in magnitude but opposite in direction

FAB=FBA\begin{align*} F_{AB} &= - F_{BA} \end{align*}

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