Related questions with answers
A 15 kg box sits on a table. The coefficient of static friction between table and box is 0.3, and the coefficient of kinetic friction is 0.2.
(a) What is the force required to start the box moving?
Solution
VerifiedGiven
We are given the mass of the box by = 15 kg and the coefficient of static friction is = 0.3 and the coefficient of kinetic friction = 0.2
Solution
The static means, the box doesn't move and the friction force between the table and the box holds the box. Hence, to just start moving the box we should apply a force equals to this friction force, so it is given by
Where is the mass of the box and is the gravitational acceleration and equals . Now we can plug our values for , and into equation (1) to get the force required to start the moving
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