a $1.59 \mathrm{~kg}$ sample of platinum at $78.2^{\circ} \mathrm{C}$ gives off $1.05 \mathrm{kcal}$ of heat $\left(c_F=0.032 \mathrm{cal} \mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1}\right)$.

Question

Quizlet Admin · Accepted Answer

b) Given information:

$$
\begin{aligned}
m&=1.59	ext{kg}=1590	ext{g}\
T_i&=78.2^{\circ}	ext{C}\
q&=-1.05	ext{kcal}=-1050	ext{cal}\
sp\ ht_{Pt}&=\mathrm{0.032cal/g^{\circ}C}
\end{aligned}
$$

a $1.59 \mathrm{~kg}$ sample of platinum at $78.2^{\circ} \mathrm{C}$ gives off $1.05 \mathrm{kcal}$ of heat $\left(c_F=0.032 \mathrm{cal} \mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1}\right)$ .

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a 1.59 kg1.59 \mathrm{~kg}1.59 kg sample of platinum at 78.2∘C78.2^{\circ} \mathrm{C}78.2∘C gives off 1.05kcal1.05 \mathrm{kcal}1.05kcal of heat (cF=0.032calg−1∘C−1)\left(c_F=0.032 \mathrm{cal} \mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1}\right)(cF​=0.032calg−1∘C−1).

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a $1.59 \mathrm{~kg}$ sample of platinum at $78.2^{\circ} \mathrm{C}$ gives off $1.05 \mathrm{kcal}$ of heat $\left(c_F=0.032 \mathrm{cal} \mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1}\right)$ .