## Related questions with answers

A $175$-$\mathrm{g}$ glider on a horizontal, frictionless air track is
attached to a fixed ideal spring with force constant $155 \mathrm{~N} / \mathrm{m}$. At
the instant you make measurements on the glider, it is moving at
$0.815$ m$/$s and is $3.00$ cm from its equilibrium point. Use $\it{energy}$
$\it{conservation}$ to find

($c$) What is the angular frequency
of the oscillations?

Solution

Verified(c) Using the expressions of $a_{max}$ and $w$ we could get the relationship between the frequency and the spring constant from Newton's law of motion by

$\begin{align*} F = m a_{m}\\ k x_m = m (\omega^{2} x_{m} )\\ \omega = \sqrt{\dfrac{k}{ m}} \tag{5} \end{align*}$

Now we can plug our values for $m$ and $k$ into equation (5) to get $\omega$

$\begin{align*} \omega &= \sqrt{\dfrac{k}{ m}} \\ &= \sqrt{\dfrac{155\mathrm{~N/m} }{ 0.175 \mathrm{~kg} }}\\ & = \boxed{29.8 \mathrm{~rad/s} } \end{align*}$

## Create an account to view solutions

## Create an account to view solutions

## More related questions

1/4

1/7