## Related questions with answers

A $2 \mathrm{~kg}$ book sits at rest on a horizontal table. The coefficient of static friction between the book and the surface is $0.40$, and the coefficient of kinetic friction is $0.20$.

(a) What is the normal force acting on the book?

(b) Is there a friction force on the book?

(c) What minimum horizontal force would be required to cause the book to slide on the table?

(d) If you give the book a strong horizontal push so that it begins sliding, what kind of force will cause it to come to rest?

(e) What is the magnitude of this force?

Solution

VerifiedA book of mass $m=2\mathrm{~kg}$ rests on a horizontal table. The coefficients of static and kinetic friction between the book and the table are $\mu_s=0.40$ and $\mu_k=0.20$, respectively.

(a)

Since the only force the book exerts on the table is its weight, the normal force on the book is equal to the book's weight:

$\begin{align*} n&=w\\ &=mg\\ &=2\mathrm{~kg} \cdot 9.80\mathrm{~\dfrac{m}{s^2}}\tag{substitute}\\ &=\boxed{19.6\mathrm{~N}}\tag{compute}\\ \end{align*}$

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