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Question

A 200.-kg satellite is in circular orbit around the Earth and moving at a speed of 5.00 km/s5.00 \mathrm{~km} / \mathrm{s}. How much work must be done to move the satellite into another circular orbit that is twice as high above the surface of the Earth?

Solution

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Knowns

  • The mass of the satellite is m=200kg\color{#c34632} m=200\, \text{kg}, and it's orbital speed is v=5.00kms=5.00×103ms\color{#c34632}v=5.00\, \dfrac{\text{km}}{\text{s}}=5.00\times 10^3\, \dfrac{\text{m}}{\text{s}}.
  • Also, the mass of the Earth is M=5.97×1024kg\color{#c34632} M=5.97\times 10^{24}\, \text{kg}, the radius of the Earth is R=6.37×106m\color{#c34632} R=6.37\times 10^6\, \text{m} and the universal gravitational constant is G=6.67×1011Nm2kg2\color{#c34632} G=6.67\times 10^{-11}\, \dfrac{\text{Nm}^2}{\text{kg}^2}
  • We need to find the required work to move the satellite on a orbit of doubled altitude.

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