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# A 25 kg chair at rest on a horizontal floor requires 165 N of horizontal force to set it in motion. Once the chair is in motion, a 127 N horizontal force keeps it moving at a constant velocity. b. Find the coefficient of kinetic friction between the chair and the floor.

Solution

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The following are the given in the problem:

\begin{align*} m &= 25 \text{ kg} \\ F_{s} &= 165 \text{ N} \\ F_{k} &= 127 \text{ N} \\ g &= 9.8 \dfrac{\text{ m}}{\text{ s}} \end{align*}

The problem wants us to determine the coefficient of kinetic friction between the chair and the floor. These can be acquired by applying and deriving the equation of coefficient of kinetic friction acting to the normal force on the chair.

\begin{align} \mu_{k} &= \dfrac{F_{k}}{F_{n}} \end{align}

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