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A 3.0-cm-thick plate has heat generated uniformly at the rate of 5×105 W/m35 \times 10^5 \mathrm{~W} / \mathrm{m}^3. One side of the plate is maintained at 200C200^{\circ} \mathrm{C} and the other side at 45C45^{\circ} \mathrm{C}. Calculate the temperature at the center of the plate for k=16 W/mCk=16 \mathrm{~W} / \mathrm{m} \cdot{ }^{\circ} \mathrm{C}.

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Answered 2 years ago
Answered 2 years ago
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Data given:

  • Thickness of a plate: x=3 cmx=3\text{ cm};
  • Heat generated per unit volume: q˙=5105  W m3\dot{q}=5\cdot 10^5~\frac{\text{ W}}{\text{ m}^3};
  • Temperature of one side of plate: T1=200  °CT_1=200~\text{ \degree C};
  • Temperature of the other side of plate: T2=45 °CT_2=45\text{ \degree C};
  • Thermal conductivity: k=16  W m °Ck=16~\frac{\text{ W}}{\text{ m}\text{ \degree C}}.

Required:

  • Temperature at the center needs to be calculated.

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