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Question

A -395 kg/s of water is to be cooled from $90^{\circ} \mathrm{C}$ to $70^{\circ} \mathrm{C}$ in a shell and tube heat exchanger having four shell passes and eight tube passes. The cooling fluid is also water with a flow rate of $5 \mathrm{~kg} / \mathrm{s}$ that enters at a temperature of $50^{\circ} \mathrm{C}$. The overall heat-transfer coefficient is $800 \mathrm{~W} / \mathrm{m}^2,{ }^{\circ} \mathrm{C}$. Determine the total area of the heat exchanger assuming all four shells are the same size.

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 12**Data given:**

- Water mass flow rate: $\dot{m}_w=5~\frac{\text{kg}}{\text{s}}$;
- Water inlet temperature: $T_{\text{w.i}}=90\text{ \degree C}$;
- Water outlet temperature: $T_{\text{w.o}}=70\text{ \degree C}$;
- $4$ shell passes and $8$ tube passes
- Cooling water mass flow rate $\dot{m}=5~\frac{\text{kg}}{\text{s}}$;
- Cooling water inlet temperature: $T_{\text{o,i}}=50\text{ \degree C}$;
- Overall heat transfer coefficient: $U=800~\frac{\text{W}}{\text{m}^2\text{ \degree C}}$;

**Required:**

- Calculate the heat transfer area if all four shells are the same size.

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