A 45.0kg45.0-\mathrm{kg} crate is dragged at constant velocity 8.20 m8.20 \mathrm{~m} across a horizontal floor with a rope making a 3030^{\circ} angle above the horizontal. The coefficient of kinetic friction is 0.2500.250. Find the work done (a) by friction.


Answered 2 years ago
Answered 2 years ago
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Given Mass of the crate = m = 45 kg Displacement of the crate = s = 8.20 m Angle of rope with the horizontal plane = θ\theta = 30o30^{o} Coefficient of kinetic friction = μ\mu = 0.25 Acceleration due to gravity = g = 9.8 ms2\frac{\text{m}}{\text{s}^{2}}

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