## Related questions with answers

A 6 kg mass traveling at speed 10 m/s strikes a stationary 6 kg mass head-on, and the two masses stick together. What was the initial total kinetic energy?

Solutions

Verified## Given:

Mass of the first object is, $m_1 = 6\ \text{kg}$

Initial speed of the first object Speed is, $10\ \text{m/s}$

Mass of the second object is, $m_2 = 6\ \text{kg}$

$\underline{\text{Identify the unknown:}}$

The initial total kinetic energy

$\underline{\text{List the Knowns:}}$

Masses: $m_1=m_2= 6 \;\mathrm{kg}$

First mass initial speed: $v_{1,i}=10 \;\mathrm{m/s}$

Second mass initial speed: $v_{2,i}=0 \;\mathrm{m/s}$

$\underline{\text{Set Up the Problem:}}$

The initial total kinetic energy of the masses is equal to the initial kinetic energy of the first mass since the second mass is initially at rest:

$KE_i=\dfrac{1}{2} mv_{1,i}^2$

$\underline{\text{Solve the Problem:}}$

$KE_i=\dfrac{1}{2} \times 6 \times (10)^2=\boxed{300 \;\mathrm{J}}$

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