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Question

A 65.0-kg firefighter climbs a flight of stairs 20.0 m high. How much work is required?

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Answered 2 years ago
Answered 2 years ago
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Given values:\text{\underline{\textbf{Given values:}}}

m=65kgm=65 \: \text{kg}

d=20md=20 \: \text{m}

The force acting on a firefighter is the gravitational force.

The work that is done by the gravitational force, we will find from the equation:

W=Fd\begin{align*} W=F \cdot d \tag{$F=m \cdot g$.}\\ \end{align*}

So, relation for work becomes:

    W=(mg)d\begin{align*} \implies W&=(m \cdot g) \cdot d\\ \end{align*}

Plug in values in above relation and solve for work:

W=65kg(9.81ms2)20mW=12753J\begin{align*} W&=65 \: \text{kg} \cdot \bigg(9.81 \: \dfrac{\text{m}}{\text{s}^2}\bigg) \cdot 20 \: \text{m}\\ W&=\boxed{12753\: \text{J}} \end{align*}

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