## Related questions with answers

A $700 \mathrm{~kg}$ horse $A$ lifts a $50 \mathrm{~kg}$ hay bale $B$ as shown. At the instant when $r=8 \mathrm{~m}$ and $\theta=60^{\circ}$, the velocity and acceleration of the horse are $2 \mathrm{~m} / \mathrm{s}$ to the right and $0.5 \mathrm{~m} / \mathrm{s}^2$ to the left, respectively. Neglecting the mass of the pulley, determine at that instant $(a)$ the tension in the cable, $(b)$ the average horizontal force between the ground and the horse's feet.

Solution

Verified$\textbf{Knowns}$:

The velocity of block A is $v_A$ = 2 m/s to the right at the instant when r = 0.8 m and $\theta$ = 30?.

$m_A$= 20 kg and $m_B$ = 25 kg

Neglecting the mass of the pulley and the effect of friction in the pulley and between block A and the horizontal surface

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