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(a) A rectangular gasoline tank can hold 50.0 kg of gasoline when full. What is the depth of the tank if it is 0.500-m wide by 0.900-m long? (b) Discuss whether this gas tank has a reasonable volume for a passenger car.

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(a)\textbf{(a)} Here the mass of the gasoline

mG=50.0kg\begin{align*} m_{\text{G}} = 50.0\,\mathrm{kg} \end{align*}

Now according to the table 11.1, the density of the rock is

ρG=0.68×103kgm3\begin{align*} \rho_{\text{G}} = 0.68\times 10^{3}\,\mathrm{kg\,m^{-3}} \end{align*}

The width of the gasoline tank

wT=0.500m\begin{align*} w_{\text{T}} = 0.500\,\mathrm{m} \end{align*}

The length of the gasoline tank

lT=0.900m\begin{align*} l_{\text{T}} = 0.900\,\mathrm{m} \end{align*}

Now as we know the volume of a rectangle tank having width wTw_{\text{T}}, length lTl_{\text{T}}, and height hTh_{\text{T}} is

VG=VT=wT×lT×hT\begin{align*} V_{\text{G}} = V_{\text{T}} = w_{\text{T}} \times l_{\text{T}} \times h_{\text{T}}\tag{1} \end{align*}

Now as we know the density is the mass per unit volume of a substance or object. In equation form, density is defined as

ρG=mGVG\begin{align*} \rho_{\text{G}} = \frac{m_{\text{G}}}{V_{\text{G}}}\tag{2} \end{align*}

Where mm is the mass and VV is the volume of the substance or the object. Now to calculate the height or depth of the tank, we use the above equations (1) and (2) and we get

ρG=mGwT×lT×hT\begin{align*} \rho_{\text{G}} & = \frac{m_{\text{G}}}{w_{\text{T}} \times l_{\text{T}} \times h_{\text{T}}}\tag{3} \end{align*}

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