Question

a Are these triangles congruent?

The given triangles are ABC\triangle ABC and DEF\triangle DEF. The vertices of the ABC\triangle ABC are at A(-2,-2), B(-2,1), and C(3,-2) while the length of the DEF\triangle DEF are DF\overline{DF}=3, DE\overline{DE}=4, and FE\overline{FE}=5.

A. Yes

B. No

b What if C in the triangle above was at (2,-2)? Would the triangles be congruent in that case?'

A. Yes

B. No

Solution

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(a)\textbf{(a)}

DEF\triangle DEF is a 3-4-5 right triangle (leg lengths: 3 and 4) while ABC\triangle ABC has leg lengths of 3 and 5 so it has a hypotenuse of 32+52=34\sqrt{3^2+5^2}=\sqrt{34}. Only one pair of corresponding sides are congruent so we can conclude that the triangles are not congruent.

So, the correct answer is choice B.\textbf{\color{#c34632}B.}

(b)\textbf{(b)}

If CC is at (2,2)(2,-2), then ABC\triangle ABC will now have leg lengths of 3 and 4 so it has a hypotenuse of 32+42=25=5\sqrt{3^2+4^2}=\sqrt{25}=5. Since three corresponding sides are congruent, then the two triangles are congruent by SSS.

So, the correct answer is choice A.\textbf{\color{#c34632}A.}

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