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Question

# A ball initially at rest rolls down a hill and has an acceleration of 3.3 $\mathrm{m} / \mathrm{s}^{2}$. If it accelerates for 7.5 s, how far will it move during this time? F. 12 m, G. 93 m, H. 120 m, J. 190 m.

Solution

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Step 1
1 of 3

$xo = 0$

$v = 0$

$a = 3.3m/s/s$

$t = 7.5s$

This is a classic plug and chug problem. Once you know your known variables you can plug it into the update position formula. From there you solve for position

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