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Question

A ball is shot from the top of a building with an initial velocity of 18 m/s18 \mathrm{~m} / \mathrm{s} at an angle θ=42\theta=42^{\circ} above the horizontal. What are the horizontal and vertical components of the initial velocity?

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EquationsEquations used:

Vxo=VocosθV_{xo}= V_{o} \cos\\\theta

Vyo=VosinθV_{yo}= V_{o} \sin\\\theta

These equations are used to find the horizontal (x) and vertical (y) components. In this case we will use this to find the initial velocity.

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