## Related questions with answers

A ball is shot from the top of a building with an initial velocity of $24 \mathrm{~m} / \mathrm{s}$ at an angle $\theta=42^{\circ}$ above the horizontal. What are the horizontal and vertical components of the initial velocity?

Solution

Verified**Given:**

A ball being shot with the following specifications:

- It is shot from the top of a certain building.
- It is shot with an initial velocity of $24\text{ m}/\text{s}$.
- The launching angle is $\theta=42\degree$.

**Required:**

- To determine the components of the initial velocity in the horizontal direction and the vertical direction.

**Context:**

The components of the initial velocity are given by:

$v_{x0}=v_0\cdot \cos(\theta)\tag 1$

$v_{y0}=v_0\cdot \sin(\theta)\tag 2$

Where:

- $v_{x0}$ is the horizontal component of the initial velocity vector.
- $v_{y0}$ is the vertical component of the initial velocity vector.
- $v_0=24\text{ m}/\text{s}$ is the initial speed of the ball.

We only need to use Eqs. (1) and (2) to determine what's being requested.

**Note:** Since all the information in this problem is provided using 2 significant figures, the final results will be presented using the said amount of significant figures; however, for intermediate calculations, we may use up to 3 decimal places depending on the case, even if it means using more than 2 significant figures for those intermediate instances.

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