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Question

A ball is thrown downward with an initial velocity of 12 m/s12 \mathrm{~m} / \mathrm{s}. Using the approximate value of g=10 m/s2g=10 \mathrm{~m} / \mathrm{s}^2, what is the velocity of the ball 1.01.0 seconds after it is released?

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Given

The initial speed of the ball is v0=12 msv_0=12\ \frac{\text{m}}{\text{s}}.

Asked

It is asked of us to find the speed of the ball vv after t=1 st=1\ \text{s}.

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