Question

A ball is thrown upward from the top of a 25.0-m-tall building. The ball's initial speed is 12.0 m/s. At the same instant, a person is running on the ground at a distance of 31.0 m from the building. What must be the average speed of the person if he is to catch the ball at the bottom of the building?

Solution

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Given values:

y=25my=25\,\text{m} - the height of the building

v0=12msv_0=12\,\frac{\text{m}}{\text{s}} - the initial speed of the ball

x=31mx=31\,\text{m} - the distance of a person from a building


Required:

It is necessary to determine the speed of a man so that he can catch the ball falling from the building.

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