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Question

A basketball is shot from an initial height of 2.40 m2.40 \mathrm{~m} (Fig. 3-63) with an initial speed of v0=12 m/sv_0=12 \mathrm{~m} / \mathrm{s} directed at an angle θ0=35\theta_0=35^{\circ} above the horizontal. How far from the basket was the player if he made a basket?

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Δy=0.65mvo=12m/sθ=35°Δx=?\Delta y= 0.65m \\ v_{o}= 12 m/s \\ \theta = 35\text{\textdegree} \\ \Delta x= ?

Writing down all knowns and the unknown will help to see what equations we can work with. Note: Δy\Delta y is the vertical distance between where the player throws the ball to where it hits the basket.

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