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Question

A beam of light traveling in an unknown material encounters a boundary with flint glass (n = 1.66). If the critical angle for total internal reflection is 3232^{\circ}, what is the index of refraction of the unknown material?

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Snell Law states:

n1sinθ1=n2sinθ2n_1\sin\theta_1=n_2\sin\theta_2

Where n1n_1 and n2n_2 are the indexes of refraction respectively of the medium 1 and 2, θ1\theta_1 is the angle of the ray to the normal in medium 1 and θ2\theta_2 is the angle of the ray to the normal in medium 2.

Total internal reflection can happen when light is trying to enter a medium with a lower index of refraction, we call the first angle at which we observe this phenomenon the critical angle θc\theta_c, at this angle, the light travels parallel to the surface separating the two mediums yielding a 90o90^o degree angle with the normal.

We can then assert the following:

n1sinθc=n2sin90on_1\sin\theta_c=n_2\sin 90^o

n1=n2sinθc=1.66sin32o=3.13n_1=\frac{n_2}{\sin\theta_c}=\frac{1.66}{\sin 32^o}=\boxed{3.13}

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