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Question

A bowling ball has a mass of 6 kg6 \mathrm{~kg} and a speed of 1.5 m/s1.5 \mathrm{~m} / \mathrm{s}. A baseball has a mass of 0.12 kg0.12 \mathrm{~kg} and a speed of 40 m/s40 \mathrm{~m} / \mathrm{s}. Which ball has the larger momentum?

Solution

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Answered 1 year ago
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In this problem, we are given a bowling ball of mass m1=6 kgm_1 = 6 \text{ kg} and speed of v1=1.5 m/sv_1 = 1.5\text{ m/s} and a baseball of mass m2=0.12 kgm_2 = 0.12 \text{ kg} and speed of v2=40 m/sv_2 = 40\text{ m/s}. The momentum pp of an object is given by the formula:

p=mvp =mv

Substituting the given data, we have for the bowling ball:

p1=(6)(1.5)=9 kg m/sp_1 = \left(6\right) \left(1.5 \right) = 9 \text{ kg m/s}

And for the base ball:

p2=(0.12)(40)=4.8 kg m/sp_2 = \left(0.12\right) \left(40 \right) = 4.8 \text{ kg m/s}

Therefore, the bowling ball\boxed{\text{bowling ball}} has a larger momentum.

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