## Related questions with answers

A bowling ball has a mass of $6 \mathrm{~kg}$ and a speed of $1.5 \mathrm{~m} / \mathrm{s}$. A baseball has a mass of $0.12 \mathrm{~kg}$ and a speed of $40 \mathrm{~m} / \mathrm{s}$. Which ball has the larger momentum?

Solution

VerifiedIn this problem, we are given a bowling ball of mass $m_1 = 6 \text{ kg}$ and speed of $v_1 = 1.5\text{ m/s}$ and a baseball of mass $m_2 = 0.12 \text{ kg}$ and speed of $v_2 = 40\text{ m/s}$. The momentum $p$ of an object is given by the formula:

$p =mv$

Substituting the given data, we have for the bowling ball:

$p_1 = \left(6\right) \left(1.5 \right) = 9 \text{ kg m/s}$

And for the base ball:

$p_2 = \left(0.12\right) \left(40 \right) = 4.8 \text{ kg m/s}$

Therefore, the $\boxed{\text{bowling ball}}$ has a larger momentum.

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