Question

A box contains N identical gas molecules equally divided between its two halves. For N = 200, what is the percentage of the time the system spends in the central configuration?

Solution

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Answered 9 months ago
Answered 9 months ago
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(i) Calculation:

p=WNtotalp = \dfrac{ W }{ N_{total} }

Expression for the percentage. Substitute values from part (g) and (h)

p=9.3×10581.607×1060×100%p= \dfrac{ 9.3 \times 10^{58} }{ 1.607 \times 10^{60} } \times 100 \%

p=5.787%p= \boxed{5.787 \%}

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