Question

(a) Calculate the ratio of Kα\mathrm{K}_{\alpha} wavelengths for uranium and carbon. (b) Calculate the ratio of Lα\mathrm{L}_{\alpha} wavelengths for platinum and calcium.

Solution

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Expression for KαK_{\alpha} is

λKα=43R1(Z1)2.\begin{align*} \lambda_{K_{\alpha}} &= \frac{4}{3 R} \frac{1} { \left( Z - 1 \right)^2} \tag{1}. \end{align*}

We are asked to calculate ratio of KαK_{\alpha} wavelengths for uranium and carbon, which have atomic number of 92 and 6. So, using eqaution (1), we get

λKα,UλKα,C=1(921)21(61)2λKα,UλKα,C=52912λKα,UλKα,C=3.02103\begin{align*} \frac{ \lambda_{K_{\alpha}, U}}{ \lambda_{K_{\alpha}, C}} &= \frac{\frac{1} { \left( 92 - 1 \right)^2}}{\frac{1} { \left( 6 - 1 \right)^2}} \\ \frac{ \lambda_{K_{\alpha}, U}}{ \lambda_{K_{\alpha}, C}} &= \frac{5^2}{91^2} \\ \frac{ \lambda_{K_{\alpha}, U}}{ \lambda_{K_{\alpha}, C}} &= \boxed{3.02 \cdot 10^{-3} } \end{align*}

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