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Question

a. Calculate the solution set and
b. Demonstrate that your solutions are right by drawing the graphs, preferably by computer.
x2+2y2=33x^2+2 y^2=33\

x2+y2+2x=19x^2+y^2+2 x=19

Solution

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Answered 2 years ago
Answered 2 years ago
Step 1
1 of 4

We have to solve the system

x2+2y2=33x2+y2+2x=19\begin{aligned} x^2+2y^2 &= 33\\ x^2+y^2+2x &= 19 \end{aligned}

If we multiply the second equation by 2-2, we get

2x22y24x=38-2x^2-2y^2-4x = -38

Adding this equation to the first one, 2y22y^2 cancels and we get

x22x24x=3338write the equationx24x=5subtract x22x2 and 3338x24x+5=0transfer 5 leftx2+4x5=0multiply both sides by 1x2+5xx5=0write 4x as 5xxx(x+5)(x+5)=0extract x and 1(x+5)(x1)=0extract x+5\begin{aligned} x^2-2x^2-4x &= 33-38 && \text{write the equation}\\ -x^2-4x &= -5 && \text{subtract }x^2-2x^2\text{ and }33-38\\ -x^2-4x+5 &= 0 && \text{transfer }-5\text{ left}\\ x^2+4x-5 &= 0 && \text{multiply both sides by }-1\\ x^2+5x-x-5 &=0 && \text{write }4x\text{ as }5x-x\\ x(x+5)-(x+5) &= 0 && \text{extract }x\text{ and }-1\\ (x+5)(x-1) &= 0 && \text{extract }x+5 \end{aligned}

From x+5=0x+5=0 we get a solution x1=5x_1=-5 and from x1=0x-1=0 we get a solution x2=1x_2=1.

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