## Related questions with answers

A capillary tube of 1.2 mm diameter is immersed vertically in water exposed to the atmosphere. Determine how high water will rise in the tube. Take the contact angle at the inner wall of the tube to be $6^\circ$ and the surface tension to be 1.00 N/m.

Solution

VerifiedTo solve this problem use this formula from the book 2-42 which is defined by the height of the water rise in the tube, density of the water, acceleration due to gravity, surface tension and the contact angle at the inner wall of the tube,

$\begin{align*} &h = \frac{2 \sigma_s}{\rho g R} \cdot \cos\phi\\ \end{align*}$

Calculate the values of the height of the water in the tube by inserting the given values,

$\begin{align*} &h = \frac{2 \cdot 1}{1000 \cdot 9.81 \cdot 0.0006} \cdot \cos(6^o)\\ &h = \frac{2 \cdot 1}{1000 \cdot 9.81 \cdot 0.0006} \cdot 0.9945\\ &h = 0.3379 \text{ m}\\ \end{align*}$

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